Examples in PhysicsMacmillan and Company, 1888 - 260 páginas |
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Página 5
... and Quantity . The practical unit of current is the ampère , and is one - tenth ( 1071 ) of the C.G.S. electro - magnetic unit of current . It follows that the coulomb , or practical unit of quant is. § 5 ] 5 C.G.S. UNITS.
... and Quantity . The practical unit of current is the ampère , and is one - tenth ( 1071 ) of the C.G.S. electro - magnetic unit of current . It follows that the coulomb , or practical unit of quant is. § 5 ] 5 C.G.S. UNITS.
Página 6
... ampère to flow through it . The ohm is theref equal to 109 C.G.S. units of resistance . Material standards , intended to represent the ol as above defined , were issued by the B.A. co mittee , but their resistance is now found be ...
... ampère to flow through it . The ohm is theref equal to 109 C.G.S. units of resistance . Material standards , intended to represent the ol as above defined , were issued by the B.A. co mittee , but their resistance is now found be ...
Página 205
... 1. An incandescent lamp takes a current of 0.7 ampère , and the E. M. F. between its terminals is found to be 98 volts : what is its resistance ? Since C is expressed in ampères and E in volts CHAPTER X CHAPTER X CURRENT ELECTRICITY.
... 1. An incandescent lamp takes a current of 0.7 ampère , and the E. M. F. between its terminals is found to be 98 volts : what is its resistance ? Since C is expressed in ampères and E in volts CHAPTER X CHAPTER X CURRENT ELECTRICITY.
Página 206
... ampère is produced , and the potential difference between the battery poles falls to 9 volts . Find the resistance of the wire and the internal resistance of the battery . The resistance ( R ) of the wire is the ratio of the difference ...
... ampère is produced , and the potential difference between the battery poles falls to 9 volts . Find the resistance of the wire and the internal resistance of the battery . The resistance ( R ) of the wire is the ratio of the difference ...
Página 207
Daniel Evan Jones. A milli - ampère is one - thousandth of an ampère , so that the required current is 0.008 ampère . By Ohm's law , C = 1.04 n / ( 30 n + 1000 ) , and this = 0.008 , .. 1.04 n = 0.24n + 8 , i.e. 0.8n = 8 , and n = 10 . 4 ...
Daniel Evan Jones. A milli - ampère is one - thousandth of an ampère , so that the required current is 0.008 ampère . By Ohm's law , C = 1.04 n / ( 30 n + 1000 ) , and this = 0.008 , .. 1.04 n = 0.24n + 8 , i.e. 0.8n = 8 , and n = 10 . 4 ...
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acceleration amount of heat ampère Assistant Master atmospheric pressure barometer barometric height battery body of mass C.G.S. units Calculate calorimeter Camb Cambridge cells charge circuit coefficient of expansion College column constant containing copper cubic centimetres cubic foot cylindrical deflection denote density diameter distance dynes electricity electromotive force ELEMENTARY equal equation ergs expressed Fcap feet per second find the specific focal length foot-pounds galvanometer glass grammes GREEK heat-units horse-power Illustrated immersed internal resistance iron kilogramme kinetic energy latent heat lens liquid litre logarithm magnetic Matric measure melted mercury metres per second miles mirror mixture ohms pendulum piston placed pole potential poundals pounds pounds weight produced Prof Professor prove radius revised School specific gravity specific heat sphere square centimetre square inch steam string surface temperature tube unit of length velocity vertical vessel volume weight per square wire
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