| Samuel H. Winter - 1867 - 468 páginas
...equilibrium, prove that f '. QI Bi;sin QOR : sin ROF : sin POQ. Three forces are represented in direction by the perpendiculars drawn from the vertices of a triangle to the opposite sides, and are inversely proportional to those perpendiculars; prove that they are in equilibrium. 3. Find... | |
| J W. Mulcaster - 1871 - 242 páginas
...OQ, through P, P v Q, is isosceles and right-angled. 29. Three forces are represented in direction by the perpendiculars drawn from the vertices of a triangle to the opposite sides, and are inversely proportional to those perpendiculars; prove that they are in equilibrium. 30. The... | |
| Euclid, James Bryce, David Munn (F.R.S.E.) - 1874 - 236 páginas
...right angle, (I. Def. 8.) and OD is perpendicular to BC. QED Cor. — Hence it follows that the three perpendiculars drawn from the vertices of a triangle to the opposite sides, meet in the same point. Let AD, BE, CF bo the three perpendiculars from the angles A, B, C of the triangle... | |
| Dublin city, univ - 1876 - 420 páginas
...his father gets $s. a day ? MR. BURNSIDE. 7. Show how to inscribe a square in any given triangle. 8. The perpendiculars drawn from the vertices of a triangle to the opposite sides meet in a point. 9. Prove that the sum of the squares on the diagonals of a parallelogram is equal... | |
| Elias Loomis - 1877 - 458 páginas
...Therefore, Prop. IV., the three lines AD, BE, CF pass through the same point. PROPOSITION VI. 90. The three perpendiculars drawn from the vertices of a triangle to the opposite sides meet in a point. Let ABC be a triangle, and let AD, BE, CF be drawn from the vertices perpendicular... | |
| Edward Albert Bowser - 1880 - 334 páginas
...need not necessarily tarry till he has mastered all the examples in any one article.] 1. Prove that the perpendiculars drawn from the vertices of a triangle to the opposite sides meet in a point. Let ABC be the triangle ; AF, BE, CD the perpendiculars. Assume AX and AY as the rectanguE... | |
| Franklin Ibach - 1882 - 208 páginas
...AED = A BED, and BD = AD=IAC. (63) (138). (45) (83) ELEMENTS OF PLANE GEOMETRY. THEOREM XLIX. 143. The perpendiculars drawn from the vertices of a triangle to the opposite sides meet in a common point. In the A ABC, let AD, BE, and CF be the _Ls from the vertices to the opposite... | |
| Benjamin Franklin Finkel - 1888 - 518 páginas
...and escribed circles of the triangle. The Pedal Triangle is a triangle formed by joining the feet of the perpendiculars drawn from the vertices of a triangle to the opposite bides. The Orthocenter is the point of intersection of these perpendiculars. Medial Lines, or Medians,... | |
| W. H. Laverty - 1889 - 256 páginas
...one-twelfth of the weight, compare the acceleration with that of gravity. 21. Forces act for a moment along the perpendiculars drawn from the vertices of a triangle to the opposite sides. Find their relative magnitudes that for the moment there may be no acceleration. 22. Three equal perfectly... | |
| Edward Albert Bowser - 1890 - 420 páginas
...angles A and B, find the value of the angle AOB. D/C Proposition 43. Theorem. 170. The perpendiculars from the vertices of a triangle to the opposite sides are concurrent. Hyp. Let ABC be a A , and RX— AD,' BE, CF,the three J_s from \ , B< A, B, C to the opp. sides. \... | |
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