Materials and Construction: A Theoretical and Practical Treatise on the Strains, Designing, and Erection of Works of ConstructionC. Lockwood and Company, 1881 - 249 páginas |
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Página 45
... complete it must also be added to the other side of the equation , that the two sides may remain of equal value . We must see what is required to com- plete the square . Let a b c d , Fig . 22 , be a square , supposed to represent the ...
... complete it must also be added to the other side of the equation , that the two sides may remain of equal value . We must see what is required to com- plete the square . Let a b c d , Fig . 22 , be a square , supposed to represent the ...
Página 46
... complete the square , but 2 y = l , must be added to each side of the equa- y = = 2 ; hence ( 1 ) tion , and we get— 82-18 + 12 12 12 4 4 6 has been seen to -- 12 , 12 1 72 12 1 = 4 12 ' % -y or x- 2 be the root of the square we have ...
... complete the square , but 2 y = l , must be added to each side of the equa- y = = 2 ; hence ( 1 ) tion , and we get— 82-18 + 12 12 12 4 4 6 has been seen to -- 12 , 12 1 72 12 1 = 4 12 ' % -y or x- 2 be the root of the square we have ...
Página 57
... complete the parallelogram Ap oq , making op parallel to A B and o q parallel to A C. Then the thrusts on AB and AC ... completing the parallelogram Buƒv , uf or Bv will be the ver- tical component , and be- u V A q W H K W Fig . 27 ...
... complete the parallelogram Ap oq , making op parallel to A B and o q parallel to A C. Then the thrusts on AB and AC ... completing the parallelogram Buƒv , uf or Bv will be the ver- tical component , and be- u V A q W H K W Fig . 27 ...
Página 59
... complete the parallelogram IHks , then I will be the horizontal strain upon the bar IJ . But because H k , I ≈ are opposite sides of a parallelo- gram , they are equal , and the horizontal strain on IJ is equal to Hk . We have then the ...
... complete the parallelogram IHks , then I will be the horizontal strain upon the bar IJ . But because H k , I ≈ are opposite sides of a parallelo- gram , they are equal , and the horizontal strain on IJ is equal to Hk . We have then the ...
Página 61
... complete the parallelogram b m no , then bo or mn will equal the strain put upon bg by that coming down a b ... completing the parallelogram kpr q , and arguing upon the similarity of the triangles krq , kfh . The total pull upon the ...
... complete the parallelogram b m no , then bo or mn will equal the strain put upon bg by that coming down a b ... completing the parallelogram kpr q , and arguing upon the similarity of the triangles krq , kfh . The total pull upon the ...
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Materials and Construction: A Theoretical and Practical Treatise on the ... Francis Campin Sin vista previa disponible - 2016 |
Términos y frases comunes
abutment acting angle irons angle of repose arch beam bolts bottom flange bracing bridge calculated carried cast iron centre of gravity cloth boards column complete the parallelogram compression cross girders crown cubic foot curve deflection depth determined diagonal diameter direction distance distributing girder Edition Engineer equal factor of safety feet force formula friction hence Illustrations inch thick inclined bar joint length lineal foot load main girder masonry material maximum strain modulus of elasticity molecules multiplied neutral axis numerous parallelogram of forces pier plates practical pressure radius ratio right angles rivet area rivet holes rivets road girder SCOTT BURN sectional area sectional square inch shearing shearing strain side span strength stress structure surface taken tensile tension timber tion top flange Treatise triangle voussoir weight wrought iron
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