Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle, and the Geometry of Solids; to which are Added, Elements of Plane and Spherical TrigonometryW.E. Dean, 1836 - 311 páginas |
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Resultados 1-5 de 62
Página 10
... bisected , or di- vided into two equal parts by the line CD , mak- ing the angle ACD equal to the angle BCD . Then ... bisecting the vertical angle of an isosceles tri- angle is perpendicular to its base , and divides that base into two ...
... bisected , or di- vided into two equal parts by the line CD , mak- ing the angle ACD equal to the angle BCD . Then ... bisecting the vertical angle of an isosceles tri- angle is perpendicular to its base , and divides that base into two ...
Página 14
... bisected , it may be demonstrated that the angle BCG , that is ( 8. 1. ) the angle ACD , is greater than the angle ABC . PROP . X. THEOR . G Any two angles of a triangle are together less than two right angles . Let ABC be any triangle ...
... bisected , it may be demonstrated that the angle BCG , that is ( 8. 1. ) the angle ACD , is greater than the angle ABC . PROP . X. THEOR . G Any two angles of a triangle are together less than two right angles . Let ABC be any triangle ...
Página 33
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal ... bisected by the straight line AF . SCHOLIUM . B D J 01S E с By the same construction , each of the halves BAF , CAF ...
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal ... bisected by the straight line AF . SCHOLIUM . B D J 01S E с By the same construction , each of the halves BAF , CAF ...
Página 34
... bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it into two equal parts . Describe ( Prob . 1. ) upon it an equilateral triangle ABC , and ...
... bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line ; it is required to divide it into two equal parts . Describe ( Prob . 1. ) upon it an equilateral triangle ABC , and ...
Página 35
... bisect ( Prob . 5. ) FG in H , and join CF , CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . E H GB D Because FH is equal to HG , and HC common to the two triangles FHC ...
... bisect ( Prob . 5. ) FG in H , and join CF , CH , CG ; the straight line CH , drawn from the given point C , is perpendicular to the given straight line AB . E H GB D Because FH is equal to HG , and HC common to the two triangles FHC ...
Otras ediciones - Ver todas
Elements of Geometry: Containing the First Six Books of Euclid, with a ... John Playfair Vista de fragmentos - 1836 |
Términos y frases comunes
ABC is equal ABCD adjacent angles altitude angle ABC angle ACB angle BAC angles equal base BC bisected centre chord circle ABC circumference cosine cylinder demonstrated diameter divided draw Prob equal and similar equal angles equiangular equilateral equilateral polygon equimultiples Euclid exterior angle fore four right angles given straight line greater Hence hypotenuse inscribed join less Let ABC Let the straight magnitudes meet multiple opposite angle parallel parallelogram parallelopiped perpendicular polygon prism PROP proposition quadrilateral radius ratio rectangle contained rectilineal figure remaining angle right angled triangle SCHOLIUM segment semicircle shewn side BC sine solid angle solid parallelopiped spherical angle spherical triangle square straight line BC THEOR third touches the circle triangle ABC triangle DEF wherefore