The practice and theory of arithmetic |
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Página ix
... debt due at a given time 85 XI . - COMMISSION , BROKERAGE , INSURANCE . Definitions To find the commission , or brokerage , on a given sum 87 To find the expense of insuring a given sum 8335 87 89 To find what sum must be insured to ...
... debt due at a given time 85 XI . - COMMISSION , BROKERAGE , INSURANCE . Definitions To find the commission , or brokerage , on a given sum 87 To find the expense of insuring a given sum 8335 87 89 To find what sum must be insured to ...
Página 76
... debt in consideration of its being paid before it is legally due . Def . 7. The present worth of a sum of money , due at a certain time , is the difference between the Principal and Discount , or is the sum , which , put out to interest ...
... debt in consideration of its being paid before it is legally due . Def . 7. The present worth of a sum of money , due at a certain time , is the difference between the Principal and Discount , or is the sum , which , put out to interest ...
Página 85
... debt , and subtract it from the debt ; the difference is the discount . Rule 2. Find the interest on the debt for the given time , and also the amount of £ 1 for the given time ; the ratio of the former to the latter is the discount in ...
... debt , and subtract it from the debt ; the difference is the discount . Rule 2. Find the interest on the debt for the given time , and also the amount of £ 1 for the given time ; the ratio of the former to the latter is the discount in ...
Página 86
... debt ...... 845.816666 333 333311 845816667 = 845.816 × .113 € . 84581667 25374500 2537450 253745 25374 2537 254 25 1.11333333 ) 95.8592219 ( 86.101097 £ . 890666666 67925553 66800000 1125553 1113333 12220 11133 1087 1012 75 77 Ans ...
... debt ...... 845.816666 333 333311 845816667 = 845.816 × .113 € . 84581667 25374500 2537450 253745 25374 2537 254 25 1.11333333 ) 95.8592219 ( 86.101097 £ . 890666666 67925553 66800000 1125553 1113333 12220 11133 1087 1012 75 77 Ans ...
Página 87
... debt 20 1917 s . 12 23006 d . 75 75 1335 1869 15 115030 161042 16 20040 - 75ths of 1d . 1725466 - 75ths of 1d . 20040 ) 1725466 ( 86 £ . 160320 122266 120240 2026 20 20040 ) 40520 ( 2 s . 40080 440 12 5280 Ans . £ 86 : 2:04 . XI ...
... debt 20 1917 s . 12 23006 d . 75 75 1335 1869 15 115030 161042 16 20040 - 75ths of 1d . 1725466 - 75ths of 1d . 20040 ) 1725466 ( 86 £ . 160320 122266 120240 2026 20 20040 ) 40520 ( 2 s . 40080 440 12 5280 Ans . £ 86 : 2:04 . XI ...
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Términos y frases comunes
1st divisor abstract number annuity called ciphers column common measure compound interest COMPOUND QUANTITY cube root decimal places difference digits diminuend dividend division equal equivalent exact number EXAMPLE explain the Rule expressed farthings Find the cost Find the ratio Find the value florins gain or loss given number GIVEN SUM greater than 12 Hence higher denomination hundreds improper fraction inches increased integer less lower denomination mixed number moidore multiplicand multiplier number of decimal number of figures number of tens number of units numerator and denominator operations denoted present value prime factors Principal produce of 100 Prop proper fraction prove the Rule quotient rate per cent recurring decimal Reduce required to find result selling price shew shewn simple fraction subtract subtrahend trial-divisor varies directly vulgar fraction whole number Write yards
Pasajes populares
Página 28 - Remove the decimal point as many places to the right as there are ciphers in the multiplier.
Página 14 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Página 178 - The sum, therefore, of all the terms of both series, is equal to the sum of the first and last terms multiplied by the number of terms...
Página 152 - When a decimal number is to be divided by 10, 100, 1000, &c., remove the decimal point as many places to the left as there are ciphers in the divisor, and if there be not figures enough in the number, prefix ciphers.
Página 157 - Four quantities are in proportion when the ratio of the first to the second is equal to the ratio of the third to the fourth.
Página 10 - A Common Multiple of two or more numbers is a multiple of each of them.
Página 37 - RULE. 1. Separate the given number into periods of two figures each, by placing a dot over units, hundreds, etc.
Página 69 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Página 5 - Then multiply the divisor by this figure and subtract the product from the figures divided; to the right of the remainder bring down the next figure of the dividend and divide this number as before.
Página 105 - RULE. Multiply each quantity by its price, and divide the sum of the products by the sum of the quantities.