The practice and theory of arithmetic |
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Página 15
... result to its lowest terms . 4. If any of the fractions be mixed numbers , add the integers separately . EXAMPLES . 1. Add together , 3 , 2 , 1 , 8 . L. C. D = 2X2X3X5 = 60 . 1X30 30 = = 2 2X30 610 60 1 2 + - 3 + - + 3 4 ARITHMETICAL ...
... result to its lowest terms . 4. If any of the fractions be mixed numbers , add the integers separately . EXAMPLES . 1. Add together , 3 , 2 , 1 , 8 . L. C. D = 2X2X3X5 = 60 . 1X30 30 = = 2 2X30 610 60 1 2 + - 3 + - + 3 4 ARITHMETICAL ...
Página 17
... result to its lowest terms . EXAMPLE . Subtract from 1 % . L. C. D. 8X5 = 40 . 5 5X5 25 8 = 8X5 40 19 9X4 36 10 10X4 40 9 5 36-25 11 10 8 40 40 Or thus L. C. D. 8X540 . 9 5 9X4-5X5 ... 10 8 40 36-25 11 40 = - 40 II . TO SUBTRACT ONE ...
... result to its lowest terms . EXAMPLE . Subtract from 1 % . L. C. D. 8X5 = 40 . 5 5X5 25 8 = 8X5 40 19 9X4 36 10 10X4 40 9 5 36-25 11 10 8 40 40 Or thus L. C. D. 8X540 . 9 5 9X4-5X5 ... 10 8 40 36-25 11 40 = - 40 II . TO SUBTRACT ONE ...
Página 19
... resulting fraction is the product required . EXAMPLES . 1. Multiply by 9 . 23 23X9 -X9 = == 27 27 218 23 2 2. Multiply by 25 . 13 13X25 13X5 -X25 = - 35 35 7 65 2 9 . 7 7 པ ། 3. Multiply 213 by 3 . 17 55 2 X 3 = X3 19 19 165 13 = - = 8 ...
... resulting fraction is the product required . EXAMPLES . 1. Multiply by 9 . 23 23X9 -X9 = == 27 27 218 23 2 2. Multiply by 25 . 13 13X25 13X5 -X25 = - 35 35 7 65 2 9 . 7 7 པ ། 3. Multiply 213 by 3 . 17 55 2 X 3 = X3 19 19 165 13 = - = 8 ...
Página 19
... resulting fraction is that required . 4. If any of the simple fractions be mixed numbers , they must be reduced to improper fractions before applying the Rule . EXAMPLES . 1. Reduce of of of to a simple 20 ARITHMETICAL RULES AND ...
... resulting fraction is that required . 4. If any of the simple fractions be mixed numbers , they must be reduced to improper fractions before applying the Rule . EXAMPLES . 1. Reduce of of of to a simple 20 ARITHMETICAL RULES AND ...
Página 19
... resulting fraction is the product required . EXAMPLES . 24 1. Multiply together 3 , 1 , 31 , 33 . 7 11 24. 16 X 7X11X24X16 8 12 35 33 8X12X35X33 1X 1X2X2 = 1X1X5X3 15 +19 - = 4 E. - Division of a Fraction by an integer . ARITHMETICAL ...
... resulting fraction is the product required . EXAMPLES . 24 1. Multiply together 3 , 1 , 31 , 33 . 7 11 24. 16 X 7X11X24X16 8 12 35 33 8X12X35X33 1X 1X2X2 = 1X1X5X3 15 +19 - = 4 E. - Division of a Fraction by an integer . ARITHMETICAL ...
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Términos y frases comunes
1st divisor abstract number annuity called ciphers column common measure compound interest COMPOUND QUANTITY cube root decimal places difference digits diminuend dividend division equal equivalent exact number EXAMPLE explain the Rule expressed farthings Find the cost Find the ratio Find the value florins gain or loss given number GIVEN SUM greater than 12 Hence higher denomination hundreds improper fraction inches increased integer less lower denomination mixed number moidore multiplicand multiplier number of decimal number of figures number of tens number of units numerator and denominator operations denoted present value prime factors Principal produce of 100 Prop proper fraction prove the Rule quotient rate per cent recurring decimal Reduce required to find result selling price shew shewn simple fraction subtract subtrahend trial-divisor varies directly vulgar fraction whole number Write yards
Pasajes populares
Página 28 - Remove the decimal point as many places to the right as there are ciphers in the multiplier.
Página 14 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Página 178 - The sum, therefore, of all the terms of both series, is equal to the sum of the first and last terms multiplied by the number of terms...
Página 152 - When a decimal number is to be divided by 10, 100, 1000, &c., remove the decimal point as many places to the left as there are ciphers in the divisor, and if there be not figures enough in the number, prefix ciphers.
Página 157 - Four quantities are in proportion when the ratio of the first to the second is equal to the ratio of the third to the fourth.
Página 10 - A Common Multiple of two or more numbers is a multiple of each of them.
Página 37 - RULE. 1. Separate the given number into periods of two figures each, by placing a dot over units, hundreds, etc.
Página 69 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Página 5 - Then multiply the divisor by this figure and subtract the product from the figures divided; to the right of the remainder bring down the next figure of the dividend and divide this number as before.
Página 105 - RULE. Multiply each quantity by its price, and divide the sum of the products by the sum of the quantities.