An Introduction to Mensuration and Practical GeometryU. Hunt & son, 1833 - 288 páginas |
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Página 19
... Parallel right lines are such as are in the same plane , and which being produced ever so far both ways , do not meet . 86. A parallelogram is a quadrilateral whose opposite sides are parallel . * This figure , by working mechanics , is ...
... Parallel right lines are such as are in the same plane , and which being produced ever so far both ways , do not meet . 86. A parallelogram is a quadrilateral whose opposite sides are parallel . * This figure , by working mechanics , is ...
Página 27
... parallel to a given line AB . CASE I. When the parallel line is to pass through a given point C. G C H A n m B 1. To AB , from the point C , draw any right line Cm . 2. From the point m , with the radius mC , describe the arc Cn ...
... parallel to a given line AB . CASE I. When the parallel line is to pass through a given point C. G C H A n m B 1. To AB , from the point C , draw any right line Cm . 2. From the point m , with the radius mC , describe the arc Cn ...
Página 28
... parallel to AB . CASE II . When the parallel line is to be at a given dis tance from AB . D n m G A ទ B 1. From any two points r , s , in the line AB , with a ra dius equal to the given distance , describe the arcs , n , m . 2. Draw ...
... parallel to AB . CASE II . When the parallel line is to be at a given dis tance from AB . D n m G A ទ B 1. From any two points r , s , in the line AB , with a ra dius equal to the given distance , describe the arcs , n , m . 2. Draw ...
Página 29
... parallel to Am , by means of a parallel ruler . PROBLEM IX . To find the centre of a given circle , or one already described . * C E F 0 B A D The centre of a given circle , or of any arc of it , may also be found by joining three ...
... parallel to Am , by means of a parallel ruler . PROBLEM IX . To find the centre of a given circle , or one already described . * C E F 0 B A D The centre of a given circle , or of any arc of it , may also be found by joining three ...
Página 31
... parallel to it ; and CF will ke the third proportional required . That is CE ( A ) : CG ( B ) :: CD ( B ) : CF. PROBLEM XII . " To three given right lines , A , B , C , to find a fourth proportional . Α B D F H E 1. From the point D ...
... parallel to it ; and CF will ke the third proportional required . That is CE ( A ) : CG ( B ) :: CD ( B ) : CF. PROBLEM XII . " To three given right lines , A , B , C , to find a fourth proportional . Α B D F H E 1. From the point D ...
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Términos y frases comunes
12 feet 20 feet 9 inches ABCD abscissa ADBA altitude arch axis base Bisect breadth cask centre circular circumference cone conjugate diameter convex superficies convex surface cube root cubic inches cylinder decimal Demon diameter dimensions divided elliptic equal EXAMPLES feet 6 inches feet 9 figure find the area find the solidity fluxion foot girth give the solidity greater end groin half the arc hyperbola length less end linear side measure middle diameter middle frustrum Multiply the area multiply the sum ordinate parabola parallel pentagon pentagonal pyramid perpendicular height plane polygon PROBLEM prolate spheroid pyramid quotient radius regular polygon Required the area Required the solidity right angles right line roof segment slant height SLIDING RULE solid content solidity required specific gravity sphere spheroid square root thickness transverse diameter trapezium triangle ullage velocity versed sine wheel wine gallons yard
Pasajes populares
Página 50 - The areas of circles are to each other as the squares of their diameters.
Página 217 - Also, as a cubic foot of water weighs just 1000 ounces avoirdupois5 the numbers in the table express, not only the specific gravities of the several bodies, but also the weight of a cubic foot of each in avoirdupois ounces ; and...
Página 20 - In a right-angled triangle, the side opposite to the right angle, is called the hypothenuse ; and the other two sides are called the legs, and sometimes the base and perpendicular : thus, A, B is the base, B, C perpendicular, and A, C hypothenuse.
Página 125 - To find the solidity of a cylinder. RULE. — Multiply the area of the base by the altitude, and the product will be the solidity.
Página 192 - ... foot ; there being three stories, and three windows in each story. The height of the lower tier is 7 feet 9 inches, of the middle 6 6 of the upper 5 3| and of an oval window over the door 1 105 the common breadth of all the windows being 3 feet 9 inches. Ans. £12, Is. 8|d. PAVERS' WORK — Pavers- work is done by the square yard.
Página 21 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Página 260 - MECHANICAL POWERS are certain simple instruments employed in raising greater weights, or overcoming greater resistance than could be effected by the direct application of natural strength. They are usually accounted six in number; viz. the Lever, the Wheel and Axle, the Pulley, the Inclined Plane, the Wedge, and the Screw.
Página 96 - As the conjugate diameter is to the transverse, So is the square root of the difference of the squares of the ordinate and semi-conjugate, To the distance between the ordinate and centre.
Página 15 - The radius of a circle is a right line drawn from the centre to the circumference.
Página 54 - To find the Area of a Triangle. Rule ] . Multiply the base by the perpendicular height, and half the product will be the area.