The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected; and Some of Euclid's Demonstrations are Restored. Also the Book of Euclid's Data, in Like Manner Corrected. the first six books, together with the eleventh and twelfthJ. Nourse, London, and J. Balfour, Edinburgh, 1775 - 520 páginas |
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Página 6
... fame Number and Magnitude . " Now , this Propofition is a Theorem , not a ... Reasons , been infufficiently demonstrated fince Theon's time hitherto ... Reasoning , and of Ma Mathematical Learning , to remove such Blemishes , and ...
... fame Number and Magnitude . " Now , this Propofition is a Theorem , not a ... Reasons , been infufficiently demonstrated fince Theon's time hitherto ... Reasoning , and of Ma Mathematical Learning , to remove such Blemishes , and ...
Página 29
... fame reason , the ex- terior angle CEB of the triangle ABE is greater than BAC ; and it has been demonstrated that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC . Therefore , if ...
... fame reason , the ex- terior angle CEB of the triangle ABE is greater than BAC ; and it has been demonstrated that the angle BDC is greater than the angle CEB ; much more then is the angle BDC greater than the angle BAC . Therefore , if ...
Página 40
... fame base and between the fame parallels , are equal to one another . Let ... reason EF is equal to BC ; wherefore AD is equal to EF ; and DE is common ... fame trapezium take the triangle EAB ; the remain- ders therefore are ...
... fame base and between the fame parallels , are equal to one another . Let ... reason EF is equal to BC ; wherefore AD is equal to EF ; and DE is common ... fame trapezium take the triangle EAB ; the remain- ders therefore are ...
Página 41
... fame paral- lels AH , BG ; the paral- lelogram ABCD is equal to EFGH . Join BE , CH ; and B DE H CF G Book I ... reason , the parallelogram EFGH is equal to the fame EBCH : Therefore also the parallelogram ABCD is equal to EFGH ...
... fame paral- lels AH , BG ; the paral- lelogram ABCD is equal to EFGH . Join BE , CH ; and B DE H CF G Book I ... reason , the parallelogram EFGH is equal to the fame EBCH : Therefore also the parallelogram ABCD is equal to EFGH ...
Página 45
... fame reason , the triangle KGC is equal to the triangle KFC : Then , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to KFC ; the triangle AEK , together with the triangle KGC is equal to the triangle AHK ...
... fame reason , the triangle KGC is equal to the triangle KFC : Then , because the triangle AEK is equal to the triangle AHK , and the triangle KGC to KFC ; the triangle AEK , together with the triangle KGC is equal to the triangle AHK ...
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Términos y frases comunes
alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio biſected Book XI cafe cauſe circle ABCD circumference cone confequently conſtruction cylinder demonſtration deſcribed diameter drawn EFGH equal angles equiangular equimultiples Euclid exceſs fame multiple fame ratio fame reaſon fides fides BA fimilar firſt folid angle fore given angle given in magnitude given in poſition given in ſpecies given magnitude given ratio given ſtraight line gnomon greater join leſs line BC oppoſite parallel parallelepipeds parallelogram paſs perpendicular priſm proportionals propoſition pyramid Q. E. D. PROP rectangle contained rectilineal figure right angles ſame ſecond ſegment ſhall ſhewn ſide ſolid ſpace ſphere ſquare of AC THEOR theſe thoſe triangle ABC vertex wherefore
Pasajes populares
Página 32 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Página 165 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF.
Página 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Página 10 - When several angles are at one point B, any ' one of them is expressed by three letters, of which ' the letter that is at the vertex of the angle, that is, at ' the point in which the straight lines that contain the ' angle meet one another, is put between the other two ' letters, and one of these two is...
Página 55 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Página 32 - ... then shall the other sides be equal, each to each; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, BCA equal to the angles DEF, EFD, viz.
Página 45 - To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Página 211 - AB shall be at right angles to the plane CK. Let any plane DE pass through AB, and let CE be the common section of the planes DE, CK ; take any point F in CE, from which draw FG in the plane DE at right D angles to CE ; and because AB is , perpendicular to the plane CK, therefore it is also perpendicular to every straight line in that plane meeting it (3.
Página 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Página 304 - Thus, if B be the extremity of the line AB, or the common extremity of the two lines AB, KB, this extremity is called a point, and has no length : For if it have any, this length must either be part of the length of the line AB, or of the line KB.