The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected; and Some of Euclid's Demonstrations are Restored. Also the Book of Euclid's Data, in Like Manner Corrected. the first six books, together with the eleventh and twelfthJ. Nourse, London, and J. Balfour, Edinburgh, 1775 - 520 páginas |
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Página 51
... Gnomon . Thus the pa- ' rallelogram HG , toge- ' ther with the comple- * ments AF , FC , is thegno- F ' mon , which is more brief- H K ly expressed by the letters AGK , or EHC which are B G C ، at the opposite angles of • the ...
... Gnomon . Thus the pa- ' rallelogram HG , toge- ' ther with the comple- * ments AF , FC , is thegno- F ' mon , which is more brief- H K ly expressed by the letters AGK , or EHC which are B G C ، at the opposite angles of • the ...
Página 55
... gnomon CMG ; Cor . 44 therefore the gnomon CMG is equal to the rectangle AD , DB : To each of these add LG , which is equal to the square of CD ; therefore the gnomon CMG together , with LG , is equal to the rectangle AD , DB , together ...
... gnomon CMG ; Cor . 44 therefore the gnomon CMG is equal to the rectangle AD , DB : To each of these add LG , which is equal to the square of CD ; therefore the gnomon CMG together , with LG , is equal to the rectangle AD , DB , together ...
Página 56
... gnomon CMG and the figure LG : But the gnomon CMG and LG make up the whole figure CEFD , which is the square of CD ; therefore the rectangle AD , DB , together with the square of CB , is e- qual to the square of CD . Wherefore , if a ...
... gnomon CMG and the figure LG : But the gnomon CMG and LG make up the whole figure CEFD , which is the square of CD ; therefore the rectangle AD , DB , together with the square of CB , is e- qual to the square of CD . Wherefore , if a ...
Página 57
... gnomon AKF together with the square CK ; therefore the gnomon AKF , toge - H G K ther with the square CK , is double : of AK : But twice the rectangle AB , BC is double of AK , for BK is e- qual to BC : Therefore the gno- mon AKF ...
... gnomon AKF together with the square CK ; therefore the gnomon AKF , toge - H G K ther with the square CK , is double : of AK : But twice the rectangle AB , BC is double of AK , for BK is e- qual to BC : Therefore the gno- mon AKF ...
Página 58
... gnomon AOH was demonstrated to be quadruple of AK ; therefore four times the rectangle AB , BC is equal to the gnomon AOH . d Cor . 4. 2. To each of these add XH , which is equal d to the square of AC : Therefore four times the ...
... gnomon AOH was demonstrated to be quadruple of AK ; therefore four times the rectangle AB , BC is equal to the gnomon AOH . d Cor . 4. 2. To each of these add XH , which is equal d to the square of AC : Therefore four times the ...
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Términos y frases comunes
alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio biſected Book XI cafe cauſe circle ABCD circumference cone confequently conſtruction cylinder demonſtration deſcribed diameter drawn EFGH equal angles equiangular equimultiples Euclid exceſs fame multiple fame ratio fame reaſon fides fides BA fimilar firſt folid angle fore given angle given in magnitude given in poſition given in ſpecies given magnitude given ratio given ſtraight line gnomon greater join leſs line BC oppoſite parallel parallelepipeds parallelogram paſs perpendicular priſm proportionals propoſition pyramid Q. E. D. PROP rectangle contained rectilineal figure right angles ſame ſecond ſegment ſhall ſhewn ſide ſolid ſpace ſphere ſquare of AC THEOR theſe thoſe triangle ABC vertex wherefore
Pasajes populares
Página 32 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Página 165 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF.
Página 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Página 10 - When several angles are at one point B, any ' one of them is expressed by three letters, of which ' the letter that is at the vertex of the angle, that is, at ' the point in which the straight lines that contain the ' angle meet one another, is put between the other two ' letters, and one of these two is...
Página 55 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Página 32 - ... then shall the other sides be equal, each to each; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, BCA equal to the angles DEF, EFD, viz.
Página 45 - To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Página 211 - AB shall be at right angles to the plane CK. Let any plane DE pass through AB, and let CE be the common section of the planes DE, CK ; take any point F in CE, from which draw FG in the plane DE at right D angles to CE ; and because AB is , perpendicular to the plane CK, therefore it is also perpendicular to every straight line in that plane meeting it (3.
Página 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Página 304 - Thus, if B be the extremity of the line AB, or the common extremity of the two lines AB, KB, this extremity is called a point, and has no length : For if it have any, this length must either be part of the length of the line AB, or of the line KB.