 Two solutions exist so long as both values of c are positive, and less than 180°, that is, so long as sin c is positive. Now when a differs more from 90° than b, we have (neglecting the signs for a moment), cos a > cos...  Trigonometry for Beginners - Página 135por John Bascombe Lock - 1896 - 210 páginasVista completa - Acerca de este libro
 | William Chauvenet - 1852 - 268 páginas
...o cos A Two solutions exist so long as both values of c are positive, and less than 180°, that is, so long as sin c is positive. Now when a differs more...than b, we have, (neglecting the signs for a moment), cos a > cos b > cos b cos c therefore the numerator of the above value of sin c has the sign of cos... | |
 | William Chauvenet - 1856 - 272 páginas
...solutions exist so long as both values of с are positive, and less than 180°, that is, so long as sin с is positive. Now when a differs more from 90° than b, we have, (neglecting the signs for a moment), cos a > cos b > cos b cos с therefore the numerator of the above value of sin с has the sign of cos... | |
 | William Chauvenet - 1924 - 268 páginas
...It cos A Two solutions exist so long as both values of c are positive, and less than 180°, thai is, so long as sin c is positive. Now when a differs more from 90° than 4, we have, (neglecting the signs for a moment), cos a > cos b > cos b eos e therefore the numerator... | |
 | William Chauvenet - 1875 - 270 páginas
...differs more from 90° than b, we have, (neglecting the signs for a moment), cos a > cos b > cos 4 cos c therefore the numerator of the above value of sin c has the sign of cos e. But by Art. 69, VI., a and A are in the same quadrant, and cos a and cos A have the same sign ;... | |
 | Henry Nathan Wheeler - 1876 - 204 páginas
...o cos A Two solutions exist so long as both values of c are positive, and less than 180°, that is, so long as sin c is positive. Now when a differs more...numerator of the above value of sin c has the sign of coa a. But by § 2 n, a and A are in the same quadrant, and cos a and cos A have the suine sign ; consequently... | |
 | Henry Nathan Wheeler - 1886 - 250 páginas
...o cos A Two solutions exist so long as both values of c are positive, and less than 180°, that is, so long as sin c is positive. Now when a differs more...than b, we have (neglecting the signs for a moment), cos a > cos 6 > cos 6 cos c, therefore the numerator of the above value of sin c has the sign of cos... | |
 | Henry Nathan Wheeler - 1876 - 254 páginas
...solutions exist so long as both values of с are positive. and less than 180°. that is. so long as sin с is positive. Now when a differs more from 90° than b. we have (neglecting the signs for a moment), cos о > сoя 6 > cos b cos c. therefore the numerator of the above value of sin e has the sign of... | |
 | Henry Nathan Wheeler - 1876 - 218 páginas
...differs more from 90° than b, we have (neglecting .the signs for a moment), cos a > cos b > cos b cos c, therefore the numerator of the above value of sin c has the sign of cos a. But by § 2 n, a and A are in the same quadrant, and cos a and cos A have the same sign ; consequently also,... | |
 | Henry Nathan Wheeler - 1878 - 198 páginas
...and less than 180°, that is, so long as sin c ia positive. Now when a differs more from 90° than 6, we have (neglecting the signs for a moment), therefore...above value of sin c has the sign of cos a. But by § 2 n, a and A are in the "same quadrant, and cos a and cos A have the same sign ; consequently also,... | |
 | Henry Nathan Wheeler - 1876 - 246 páginas
...and less than 180°, that is, so long as sin с is positive. Now when a diners more from 90° than 6, we have (neglecting the signs for a moment), therefore the numerator of the above value of sin с has the sign of cos a. But by § 2 n, a and A are in the same quadrant, and cos a and cos A have... | |
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