Elements of Geometry: Being Chiefly a Selection from Playfair's GeometryA. Walker, 1829 - 186 páginas |
Dentro del libro
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Página
... bisect each other , & For angled read angles For , read . For contains read contain For --- ABDE read = } AB— \ DE For time read times Add , Algebraically . Let a denote the great- er part , and the less ; then a + x is the sum of the ...
... bisect each other , & For angled read angles For , read . For contains read contain For --- ABDE read = } AB— \ DE For time read times Add , Algebraically . Let a denote the great- er part , and the less ; then a + x is the sum of the ...
Página 29
... also the angle BAC is equal to EDF . Hence the triangles ABC , DEF are equal in all re- spects ( 4. 1. ) . Wherefore , if two triangles & c . Q. E. D. PROPOSITION IX . PROBLEM . To bisect a given rectilineal GEOMETRY . 29 BOOK I.
... also the angle BAC is equal to EDF . Hence the triangles ABC , DEF are equal in all re- spects ( 4. 1. ) . Wherefore , if two triangles & c . Q. E. D. PROPOSITION IX . PROBLEM . To bisect a given rectilineal GEOMETRY . 29 BOOK I.
Página 30
... bisect a given rectilineal angle ; that is , to di- vide it into two equal angles . Let BAC be the given rectilineal angle ; it is required to bisect it . Take any point D in AB , and from AC cut off AE equal to AD ( 3. 1. ) ; join DE ...
... bisect a given rectilineal angle ; that is , to di- vide it into two equal angles . Let BAC be the given rectilineal angle ; it is required to bisect it . Take any point D in AB , and from AC cut off AE equal to AD ( 3. 1. ) ; join DE ...
Página 31
... bisect the vertical angle of an equila- teral or an isosceles triangle , it will also bisect the base at right angles . For the triangles ACD , BCD are equal in all respects . PROPOSITION XI . PROBLEM . To draw a straight line at right ...
... bisect the vertical angle of an equila- teral or an isosceles triangle , it will also bisect the base at right angles . For the triangles ACD , BCD are equal in all respects . PROPOSITION XI . PROBLEM . To draw a straight line at right ...
Página 32
... bisect FG in H ( 10. 1. ) , and draw CF , CH , CG ; the A straight line CH , drawn from the given point C , is E H B D perpendicular to the given straight line AB . Because FH is equal to HG , and HC is common to the two triangles FHC ...
... bisect FG in H ( 10. 1. ) , and draw CF , CH , CG ; the A straight line CH , drawn from the given point C , is E H B D perpendicular to the given straight line AB . Because FH is equal to HG , and HC is common to the two triangles FHC ...
Otras ediciones - Ver todas
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Sin vista previa disponible - 2023 |
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Sin vista previa disponible - 2023 |
Términos y frases comunes
ABC is equal ABCD alternate angles angle ABC angle ACB angle BAC angles AGH angles equal base ABC bases and altitudes bisect centre chord circumference cone Consequently cylinder demonstrations described diagonals diameter divided draw equal angles equal arches equal bases equal circles equal to AC equiangular Euclid's Euclid's Elements exterior angle fore four quantities four right angles geometry given point given straight line gles greater Hence homologous sides intersect KLMN Let ABC meet opposite angles opposite side paral parallel lines parallel to CD parallelogram parallelopipeds perp perpendicular plane polygon prism Prop pyramid Q. E. D. COR Q. E. D. PROPOSITION radius rectangle contained right angled triangle Scholium segments semicircle side AC similar similar triangles solid square straight line &c subtended tangent THEOREM triangle ABC vertex wherefore
Pasajes populares
Página 36 - Any two sides of a triangle are together greater than the third side.
Página 80 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Página 42 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line...
Página 30 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Página 20 - LET it be granted that a straight line may be drawn from any one point to any other point.
Página 38 - Problem. At a given point in a given straight line to make a rectilineal angle equal to a given rectilineal angle.
Página 113 - Wherefore also the angle BAD is equal to the angle CAD : Therefore the angle BAC is cut into two equal angles by the straight line AD.
Página 24 - DE ; the point B shall coincide with the point E, because AB is equal to DE; and AB coinciding with DE, AC shall coincide...
Página 36 - The greater angle of every triangle is subtended by the greater side, or has the greater side opposite to it.