Elements of Geometry: Being Chiefly a Selection from Playfair's GeometryA. Walker, 1829 - 186 páginas |
Dentro del libro
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Página 25
... angles at the bases of both triangles will be equal to one another ; therefore the sides opposite to them will be equal to one another by the proposi- tion , E ED . Cor . 2. If two triangles be mutually equiangular , GEOMETRY . BOOK I. 25.
... angles at the bases of both triangles will be equal to one another ; therefore the sides opposite to them will be equal to one another by the proposi- tion , E ED . Cor . 2. If two triangles be mutually equiangular , GEOMETRY . BOOK I. 25.
Página 26
... equiangular , and have two corresponding sides equal to each other , the other corre- sponding sides will be equal , and the triangles will be equal in all respects . ED . PROPOSITION V. THEOREM . IF two sides of a triangle be equal ...
... equiangular , and have two corresponding sides equal to each other , the other corre- sponding sides will be equal , and the triangles will be equal in all respects . ED . PROPOSITION V. THEOREM . IF two sides of a triangle be equal ...
Página 27
... equiangular , Let ABC be an equilateral triangle ; then because the two sides AB , AC are equal , the angles B and C ... equiangular , ED . A PROPOSITION VI . THEOREM . * If two angles of GEOMETRY . 27 BOOK I.
... equiangular , Let ABC be an equilateral triangle ; then because the two sides AB , AC are equal , the angles B and C ... equiangular , ED . A PROPOSITION VI . THEOREM . * If two angles of GEOMETRY . 27 BOOK I.
Página 28
... equiangular triangle is also equilateral . Let ABC be an equiangular triangle ( figure to Cor . Prop . V ) ; then because the angle B is equal to C , the side AC is equal to AB ; and because the angle A is equal to C , the side BC is ...
... equiangular triangle is also equilateral . Let ABC be an equiangular triangle ( figure to Cor . Prop . V ) ; then because the angle B is equal to C , the side AC is equal to AB ; and because the angle A is equal to C , the side BC is ...
Página 45
... equiangular , and the side BC is common to both , therefore they are equal in all respects ( A ) , and the side AB is equal to CD , and the side AC to BD , and the triangle ABC to BCD . Therefore the opposite sides of a paral . are ...
... equiangular , and the side BC is common to both , therefore they are equal in all respects ( A ) , and the side AB is equal to CD , and the side AC to BD , and the triangle ABC to BCD . Therefore the opposite sides of a paral . are ...
Otras ediciones - Ver todas
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Sin vista previa disponible - 2023 |
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Sin vista previa disponible - 2023 |
Términos y frases comunes
ABC is equal ABCD alternate angles angle ABC angle ACB angle BAC angles AGH angles equal base ABC bases and altitudes bisect centre chord circumference cone Consequently cylinder demonstrations described diagonals diameter divided draw equal angles equal arches equal bases equal circles equal to AC equiangular Euclid's Euclid's Elements exterior angle fore four quantities four right angles geometry given point given straight line gles greater Hence homologous sides intersect KLMN Let ABC meet opposite angles opposite side paral parallel lines parallel to CD parallelogram parallelopipeds perp perpendicular plane polygon prism Prop pyramid Q. E. D. COR Q. E. D. PROPOSITION radius rectangle contained right angled triangle Scholium segments semicircle side AC similar similar triangles solid square straight line &c subtended tangent THEOREM triangle ABC vertex wherefore
Pasajes populares
Página 36 - Any two sides of a triangle are together greater than the third side.
Página 80 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Página 42 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line...
Página 30 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Página 20 - LET it be granted that a straight line may be drawn from any one point to any other point.
Página 38 - Problem. At a given point in a given straight line to make a rectilineal angle equal to a given rectilineal angle.
Página 113 - Wherefore also the angle BAD is equal to the angle CAD : Therefore the angle BAC is cut into two equal angles by the straight line AD.
Página 24 - DE ; the point B shall coincide with the point E, because AB is equal to DE; and AB coinciding with DE, AC shall coincide...
Página 36 - The greater angle of every triangle is subtended by the greater side, or has the greater side opposite to it.