Elements of Geometry: Being Chiefly a Selection from Playfair's GeometryA. Walker, 1829 - 186 páginas |
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Página 18
... radius ; and the curve line described by the moveable extremity of the revolving line is called the circumference of the circle . ED . 20. Cor . Hence a circle is a plane figure contained by a curve line , or circumference , and all ...
... radius ; and the curve line described by the moveable extremity of the revolving line is called the circumference of the circle . ED . 20. Cor . Hence a circle is a plane figure contained by a curve line , or circumference , and all ...
Página 85
... radius or a diameter bisect a chord , it will cut the chord at right angles ; and if it cut a chord at right angles , it will bisect the chord . 1. Let ABC be a circle , and let a diameter CD bisect any chord AB in the point F ; CD cuts ...
... radius or a diameter bisect a chord , it will cut the chord at right angles ; and if it cut a chord at right angles , it will bisect the chord . 1. Let ABC be a circle , and let a diameter CD bisect any chord AB in the point F ; CD cuts ...
Página 86
... radius ED as an axis of motion , till the point A fall on B , and the radius EA coincide with EB , it is evident that the arch AD will coincide with BD ; therefore the arch AD is equal to BD , and the arch ADB is bisected by the radius ...
... radius ED as an axis of motion , till the point A fall on B , and the radius EA coincide with EB , it is evident that the arch AD will coincide with BD ; therefore the arch AD is equal to BD , and the arch ADB is bisected by the radius ...
Página 93
... radius GB on HE ; then the radius GC will coincide with its equal HF , because the angle BGC is equal to EHF . Now it is evident that the circle ABC will coincide with the equal circle DEF , and that the arch BKC will coincide with ELF ...
... radius GB on HE ; then the radius GC will coincide with its equal HF , because the angle BGC is equal to EHF . Now it is evident that the circle ABC will coincide with the equal circle DEF , and that the arch BKC will coincide with ELF ...
Página 98
... radius DB , describe a circle cutting AB in the points C and B. Through the points C and D draw the line CDF meet- ing the circumference in F. Draw BF , which will be the per- pendicular required . For the angle CBF is in a semi- circle ...
... radius DB , describe a circle cutting AB in the points C and B. Through the points C and D draw the line CDF meet- ing the circumference in F. Draw BF , which will be the per- pendicular required . For the angle CBF is in a semi- circle ...
Otras ediciones - Ver todas
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Sin vista previa disponible - 2023 |
Elements of Geometry: Being Chiefly a Selection From Playfair's Geometry John Playfair Sin vista previa disponible - 2023 |
Términos y frases comunes
ABC is equal ABCD alternate angles angle ABC angle ACB angle BAC angles AGH angles equal base ABC bases and altitudes bisect centre chord circumference cone Consequently cylinder demonstrations described diagonals diameter divided draw equal angles equal arches equal bases equal circles equal to AC equiangular Euclid's Euclid's Elements exterior angle fore four quantities four right angles geometry given point given straight line gles greater Hence homologous sides intersect KLMN Let ABC meet opposite angles opposite side paral parallel lines parallel to CD parallelogram parallelopipeds perp perpendicular plane polygon prism Prop pyramid Q. E. D. COR Q. E. D. PROPOSITION radius rectangle contained right angled triangle Scholium segments semicircle side AC similar similar triangles solid square straight line &c subtended tangent THEOREM triangle ABC vertex wherefore
Pasajes populares
Página 36 - Any two sides of a triangle are together greater than the third side.
Página 80 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Página 42 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line...
Página 30 - To bisect a given finite straight line, that is, to divide it into two equal parts. Let AB be the given straight line : it is required to divide it intotwo equal parts.
Página 20 - LET it be granted that a straight line may be drawn from any one point to any other point.
Página 38 - Problem. At a given point in a given straight line to make a rectilineal angle equal to a given rectilineal angle.
Página 113 - Wherefore also the angle BAD is equal to the angle CAD : Therefore the angle BAC is cut into two equal angles by the straight line AD.
Página 24 - DE ; the point B shall coincide with the point E, because AB is equal to DE; and AB coinciding with DE, AC shall coincide...
Página 36 - The greater angle of every triangle is subtended by the greater side, or has the greater side opposite to it.