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" That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. "
New University Algebra - Página 31
por Horatio Nelson Robinson - 1875 - 412 páginas
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A Treatise on Algebra: Embracing, Besides the Elementary Principles, All the ...

George Roberts Perkins - 1842 - 370 páginas
...Hence, the product will be Saab X 4:aaabb=l2aaaaabbb=l2asb3. Here we discover that the exponent of a, in the product, Is equal to the sum of the exponents of a in the factors ; likewise the exponent of b, in the product, is equal to the sum of the exponents...
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Ray's Algebra, Part First: On the Analytic and Inductive Methods of ..., Parte1

Joseph Ray - 1848 - 250 páginas
...That the coefficient of any term is equal. to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 3d. That the product of like signs, gives plus in the product, and...
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The Elements of Algebra: Designed for the Use of Common Schools, Also ...

George Roberts Perkins - 1848 - 234 páginas
...by 4a362, will be, Saab X 4aaa66=12aaaaa666=12a663. From which we discover, that the exponent of a, in the product, is equal to the sum of the exponents of a in the factors ; likewise, the exponent of 6, in the product^ is equal to the sum of the exponents...
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Ray's Algebra, Part First: On the Analytic and Inductive Methods of ...

Joseph Ray - 1848 - 250 páginas
...That the coefficient of any term is equal to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 3d. That the product of like signs, gives plus in the product, and...
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Ray's Algebra Part Second: An Analytical Treatise, Designed for High Schools ...

Joseph Ray - 1852 - 408 páginas
...That the coefficient of any term is equal to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 3 d. That the product of like signs gives plus in the product, and...
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New University Algebra: A Theoretical and Practical Treatise, Containing ...

Horatio Nelson Robinson - 1863 - 432 páginas
...а'Ь' by a'b*. Since а*Ъ'= aaaa ЪЪЪ, and a*b'=aaa bb, we have • a>b'Xa'l>*=aaaabbbaaabb=a'bt. Hence, The exponent of any letter in the product is...is to be taken. In Algebra, however, a multiplier may be affected by either the plus or the minus sign ; and it is necessary to consider how the sign...
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Elements of Algebra: For Colleges, Schools, and Private Students, Libro 2

Joseph Ray - 1866 - 420 páginas
...MULTIPLICATION AND DIVISION OF QUANTITIES WITH FRACTIONAL EXPONENTS. , . It has beep shown (Art. 56) that the exponent of any letter in the product is equal to the sum of its exponents in the two factors. It will now .be shown that the lame rule applies when the exponents...
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Ray's Algebra, Part Second: An Analytical Treatise, Designed for ..., Parte2

Joseph Ray - 1852 - 422 páginas
...That the coefficient of any term is equal to the product of the coefficients of its factors. 2d. That the exponent of any letter in the product is equal to the sum of its exponents in the two factors. 8 d. That the product of like signs gives plus in the product, and...
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New University Algebra: A Theoretical and Practical Treatise Containing Many ...

Horatio Nelson Robinson - 1868 - 430 páginas
...multiply a'l* by а'Ъ*. Since a'l' = aaaalbb, and a'l' = aaa Ы, we have a'l>"y(_a'b*=aaaaoolaaabb=:a'i'. Hence, The exponent of any letter in the product is...multiplicand and multiplier. 3d. The law of signs. Jn Arithmetic, multiplication is restricted to the simple process of repeating a number; and the only...
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A Treatise on Algebra

Elias Loomis - 1868 - 386 páginas
...which is obtained by adding together 3 and 2, the exponents of the common letter a. Hence we see that the exponent of any letter in the product is equal...of this letter in the multiplicand and multiplier. 59. Hence, for the multiplication of monomials, we have the following RULE. Multiply together the coefficients...
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