Chemical CalculationsD. Van Nostrand Company, 1923 - 276 páginas |
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Página 22
... NaCl . The molecular weights being the sum of the atomic weights , are : BaCl2 Na2SO4 Ba = 137.37 Na2 = 2 ( 22.997 ) = 45.994 2 Cl = 2 ( 35.457 ) = 70.914 S = 32.064 208.284 4 0 = 4 ( 16.00 ) = 64.000 142.058 BaSO4 2NaCl Ba = 137.37 Na ...
... NaCl . The molecular weights being the sum of the atomic weights , are : BaCl2 Na2SO4 Ba = 137.37 Na2 = 2 ( 22.997 ) = 45.994 2 Cl = 2 ( 35.457 ) = 70.914 S = 32.064 208.284 4 0 = 4 ( 16.00 ) = 64.000 142.058 BaSO4 2NaCl Ba = 137.37 Na ...
Página 25
... NaCl . = 1.1207 : factor of BaSO4 to BaCl2 . 1.6432 : factor of BaSO , to Na2SO4 . = 1.9967 : factor of BaSO , to NaCl . 2 ( 58.454 ) LINE ( MAKING IT THE DENOMINATOR ) , MULTIPLY BY THE TERM OF THE DISSIMILAR UNIT . This rule of ...
... NaCl . = 1.1207 : factor of BaSO4 to BaCl2 . 1.6432 : factor of BaSO , to Na2SO4 . = 1.9967 : factor of BaSO , to NaCl . 2 ( 58.454 ) LINE ( MAKING IT THE DENOMINATOR ) , MULTIPLY BY THE TERM OF THE DISSIMILAR UNIT . This rule of ...
Página 26
... NaCl to BaCl2 . 0.8230 : factor of NaCl to Na2SO4 . 0.5008 : factor of NaCl to BaSO4 . From an inspection of these ratios it will be noted that of the twelve , BaCl2 each has its reciprocal ; ( a ) " , having its reciprocal in ( d ) ...
... NaCl to BaCl2 . 0.8230 : factor of NaCl to Na2SO4 . 0.5008 : factor of NaCl to BaSO4 . From an inspection of these ratios it will be noted that of the twelve , BaCl2 each has its reciprocal ; ( a ) " , having its reciprocal in ( d ) ...
Página 28
... NaCl + NH4HCO3 = NaHCO3 + NHẠC , 2NaHCO3 = Na2CO3 + H2O + CO2 . It is desired to know the amount of ammonia involved in the produc- tion of one ton of sodium carbonate . It is needless to calculate the amount of acid ammonium carbonate ...
... NaCl + NH4HCO3 = NaHCO3 + NHẠC , 2NaHCO3 = Na2CO3 + H2O + CO2 . It is desired to know the amount of ammonia involved in the produc- tion of one ton of sodium carbonate . It is needless to calculate the amount of acid ammonium carbonate ...
Página 36
... NaCl = AgCl + HNO3 . Ans . 1.1747 g . 54. ( a ) What is the percentage of manganese in pure potassium permanganate ( KMnO4 ) ? ( b ) If contaminated to an extent of 2.00 % of impurities ? Ans . ( a ) 34.76 % ( b ) 34.06 % 55. Dolomite ...
... NaCl = AgCl + HNO3 . Ans . 1.1747 g . 54. ( a ) What is the percentage of manganese in pure potassium permanganate ( KMnO4 ) ? ( b ) If contaminated to an extent of 2.00 % of impurities ? Ans . ( a ) 34.76 % ( b ) 34.06 % 55. Dolomite ...
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Términos y frases comunes
AgCl ammonia amount analysis approximate aqueous vapor atomic weight barium sulphate barometer boiling point bromine CaCO3 calcium Calculate the percentage Calories carbon dioxide cent Chem chemical coefficient of expansion compound constant contains corresponding cubic centimeter degrees Baumé Density of water determined element equation equivalent factor flask formula freezing point gases given gram molecule H₂O HNO3 hydrochloric acid hydrogen iodine iron kilogram liquid liter logarithm mercuric oxide mercury methane method mixed acid mixture molecular weight NaCl NaOH nitric acid nitrogen normal solution obtained oleum oxygen percentage composition platinum potassium chloride potassium permanganate pounds pressure ratio reaction relative density salt sample saturated significant figures silver chloride sinker SiO2 sodium carbonate sodium chloride sodium hydroxide specific gravity specific heat standard conditions sulphuric acid Table taken temperature titrated unit volume vacuo valence vapor density water vapor
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Página 95 - Avogadro's law states that equal volumes of all gases at the same temperature and pressure contain the same number of molecules...
Página 268 - Baume Hydrometers for use with this table must be graduated by the above formula, which formula should always be printed on the scale. Atomic weights from FW Clarke's table of 1901. О - 16. Allowance for Temperature At 10° -20° Be.— 1/30° Be.
Página 9 - The logarithm of the quotient of two positive numbers is found by subtracting the logarithm of the divisor from the logarithm of the dividend. (6) The logarithm of a power of a positive number is found by multiplying the logarithm of the number by the exponent of the power. For, N" = (oT)
Página 106 - (a) Units of Capacity. — The liter, defined as the volume occupied by a quantity of pure water at 4° C. having a mass of 1...
Página 269 - Soc., vol. 57, p. 363. AUTHORITIES — WC FERGUSON; HP TALBOT. This table has been approved and adopted as a standard by the Manufacturing Chemists' Association of the United States.
Página 88 - Marriott, so named after its discoverers, is that the volume of a gas varies inversely as the pressure to which it is subjected.
Página 140 - The atomic weight (also known as the combining weight) of an element is the ratio of the weight of an atom of that element to the weight of an atom of hydrogen. Hydrogen...
Página 58 - Thus, the reduction of the value of the modulus between the melting point of ice and the boiling point of water is...