Chemical CalculationsD. Van Nostrand Company, 1923 - 276 páginas |
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Página 30
... excess of potassium chromate from a solution containing lead chloride , how many grams of lead chloride were present ? ( c ) How many grams of lead chromate are obtained from 1.000 g . of lead chloride ? 30 CHEMICAL CALCULATIONS.
... excess of potassium chromate from a solution containing lead chloride , how many grams of lead chloride were present ? ( c ) How many grams of lead chromate are obtained from 1.000 g . of lead chloride ? 30 CHEMICAL CALCULATIONS.
Página 49
... excess of ° Bé . of required acid over 5.00 ° Bé . , the Bé . below . = the interval in ° Bé . between the points given . = 72.39 % the interval in per cent H2SO4 cor- responding to an interval of 55.00 ° Bé . 59.23 % H2SO4 ...
... excess of ° Bé . of required acid over 5.00 ° Bé . , the Bé . below . = the interval in ° Bé . between the points given . = 72.39 % the interval in per cent H2SO4 cor- responding to an interval of 55.00 ° Bé . 59.23 % H2SO4 ...
Página 93
... excess of oxygen and noting the contraction . The resulting carbon dioxide is next absorbed in potassium hydroxide and the con- traction again noted . The reactions taking place are : ( a ) 2H2 2 vol . + O2 = I vol . 2H2O o vol . ( b ) ...
... excess of oxygen and noting the contraction . The resulting carbon dioxide is next absorbed in potassium hydroxide and the con- traction again noted . The reactions taking place are : ( a ) 2H2 2 vol . + O2 = I vol . 2H2O o vol . ( b ) ...
Página 113
... excess . 57.30 - 12.60 = 44.70 c.c. is the required amount of H2 necessary for the first explosion . The reactions are : ( 1 ) N2O + H2 = N2 + H2O , x + x = x + o 2NO + H2 = N2 + H2O , 2y + y = y + o . Then the contraction due to the H2 ...
... excess . 57.30 - 12.60 = 44.70 c.c. is the required amount of H2 necessary for the first explosion . The reactions are : ( 1 ) N2O + H2 = N2 + H2O , x + x = x + o 2NO + H2 = N2 + H2O , 2y + y = y + o . Then the contraction due to the H2 ...
Página 122
... excess and by how many cubic centimeters ? ( c ) What is the total volume of the gases after explosion ? Ans . ( a ) ... excess ? Ans . No excess oxygen in excess . 251. 50 c.c. of carbon monoxide are combined with After combination 60 ...
... excess and by how many cubic centimeters ? ( c ) What is the total volume of the gases after explosion ? Ans . ( a ) ... excess ? Ans . No excess oxygen in excess . 251. 50 c.c. of carbon monoxide are combined with After combination 60 ...
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Términos y frases comunes
2HCl 2KCl acetic acid added AgBr AgCl amount analysis analyzed anhydride aqueous vapor arsenic atomic weight BaCl2 barium sulphate barometer boiling point bromine CaCO3 Calculate the percentage Calories carbon dioxide Chem chemical compound contains corresponding cubic centimeter decimal point degrees Baumé determined element equation equivalent error factor flask formula freezing point gases given H₂O HNO3 hydrochloric acid hydrogen iodide iodine iron kilogram liquid liter logarithm mercuric oxide mercury meters method mixed acid mixture molecular weight multiplied NaCl NaHCO3 NaOH neutralize nitric acid nitrogen normal solution obtained oleum oxalic oxygen platinum potassium chloride potassium permanganate pounds present pressure problem ratio reaction salt sample significant figures silver chloride sodium carbonate sodium chloride sodium hydroxide sodium sulphate specific gravity specific heat standard conditions substance sulphuric acid Table taken temperature thiosulphate tion titrated unit valence volume
Pasajes populares
Página 95 - Avogadro's law states that equal volumes of all gases at the same temperature and pressure contain the same number of molecules...
Página 268 - Baume Hydrometers for use with this table must be graduated by the above formula, which formula should always be printed on the scale. Atomic weights from FW Clarke's table of 1901. О - 16. Allowance for Temperature At 10° -20° Be.— 1/30° Be.
Página 9 - The logarithm of the quotient of two positive numbers is found by subtracting the logarithm of the divisor from the logarithm of the dividend. (6) The logarithm of a power of a positive number is found by multiplying the logarithm of the number by the exponent of the power. For, N" = (oT)
Página 106 - (a) Units of Capacity. — The liter, defined as the volume occupied by a quantity of pure water at 4° C. having a mass of 1...
Página 269 - Soc., vol. 57, p. 363. AUTHORITIES — WC FERGUSON; HP TALBOT. This table has been approved and adopted as a standard by the Manufacturing Chemists' Association of the United States.
Página 88 - Marriott, so named after its discoverers, is that the volume of a gas varies inversely as the pressure to which it is subjected.
Página 140 - The atomic weight (also known as the combining weight) of an element is the ratio of the weight of an atom of that element to the weight of an atom of hydrogen. Hydrogen...
Página 58 - Thus, the reduction of the value of the modulus between the melting point of ice and the boiling point of water is...