PROP. XVII. THEOR. A cylinder and a parallelepiped having equal bases and altitudes, are equal to one another. Let ABCD be a cylinder, and EF a parallelepiped having equal bases, viz. the circle AGB and the parallelogram EH, and having also equal altitudes; the cylinder ABCD is equal to the parallelepiped EF. If not, let them be unequal; and first, let the cylinder be less than the parallelepiped EF ; and from the parallelepiped EF let there be cut off a part EQ by a plane PQ parallel to NF, equal to the cylinder ABCD. la the circle AGB inscribe the polygon AGKBLM that shall differ from the circle by a space less than the parallelogram PH (Cor. 1. 4. 1. Sup.), and cut off from the parallelogram EH, a part OR equal to the polygon AGKBLM. The point R will fall between P and N. On the polygon AGKBLM let an upright prism AGBCD be constituted of the same altitude with the cylinder, which will therefore be less than the cylioder, because it is within it (16. 3. Sup.); and if through the point Ř a plane RS parallel to NF be made to pass, it will cut off the parallelepiped ES equal (2. Cor. 8. 3. Sup ) to the prism AGBC, because its base is equal to that of the prism, and its altitude is the same. But the prism AGBC is less than the cylinder ABCD, and the cylinder ABCD is equal to the parallelepiped EQ, by hypothesis ; therefore, ES is less than EQ, and it is also greater, which is impossible. Tbe cylinder ABCD, therefore, is not less than the parallelepiped EF; and in the same manner, it may be shewn not to be greater than EF. Therefore they are equal. Q. E. D. If a core and a cylinder have the same base and the same altitude, the cone is the third part of the cylinder. Let the cone ABCD, and the cylinder BFKG have the same base, viz. the circle BCD, and the same altitude, viz. the perpendicular from the point A upon the plane BCD, the cone ABCD is the third part of the cylinder BFKG. If not, let the cone ABCD be the third part of another cylinder LMNO, having the same altitude with the cylinder BFKG, but let the bases BCD and LIM be unequal ; and first, let BCD be greater than LIM. Then, because the circle BCD is greater than the circle LIM, a polygon may be inscribed in BCD, that shall differ from it less than LIM does (4. 1. Sup.), and which, therefore, will be greater than LIM. Let this be the polygon BECFD ; and upon BECFD, let there be constituted the pyramid ABECFD, and the prism BCFKHG. Because the polygon BECFD is greater than the circle LIM, the prism BCFKHG, is greater than the cylinder LMNO, for they have the same altitude, but the prism has the greater base. But the pyra. mid ABECFD is the third part of the prism (15. 3. Sup.) BCFKHG, therefore it is greater than the third part of the cylinder LMNO. Now, the cone ABECFD is, by hypothesis, the third part of the cylinder LMNO, therefore, the pyramid ABECFD is greater than the cone ABCD, and it is also less, because it is inscribed in the cone, which is impossible. Therefore, the cone ABCD is not less than the third part of the cylinder BFKG : And in the same manner, by circam. scribing a polygon about the circle BCD, it may be shewn that the cone ABCD is not greater than the third part of the cylinder BFKG; therefore, it is equal to the third part of that cylinder. Q. E. D. : phere, and the cone, a If a kemisphere and a cone have equal bases and altitudes, a series of cylinders may be inscribed in the hemisphere, and another series may be described about the cone, having all the same altitudes with one another, and such that their sum shall differ from the sum of the hemis by a solid less than any given solid. Let ADB be a semicircle, of which the centre is C, and let CD be. at right angles to AB ; let DB and DA be squares described on DC, draw CE, and let the figure thus constructed revolve about DC : then, the sector BCD, which is the half of the semicircle ADB, will describe a hemisphere having C for its centre (7. def. 3. Sup.), and the triangle CDE will describe a cone, having its vertex at C, and having for its base the circle (11. def. 3. Sup.) described by DE, equal to that described by BC, which is the base of the hemisphere. Let W be any given solid. A series of cylinders may be inscribed in the hemisphere ADB, and another described about the cone ECI, so that their sum shall differ from the sum of the hemisphere and the cone, by a solid less than the solid W. Upon the base of the hemisphere let a cylinder be constituted equal to W, and let its altitude be CX. Divide CD into such a number of equal parts, that each of them shall be less than CX ; let these be CH, HG, GF, and FD. Through the points F, G, H, draw FN, GO, HP parallel to CB, meeting the circle in the points K, L and M; and the straight line CE in the points Q, R and S. From the points K, L, M draw Kf, Lg, Mh perpendicular to GO, HP and CB; and from Q, R and S, draw Qq, Rr, Ss perpendicular to the same lines. It is evident, that the figure being thus constructed, if the whole revolve about CD, the rectangles Ff, Gg, Hh will describe cylinders (14. def. 3. Sup.) that will be circumscribed by the hemisphere BDA; and that the rectangles DN, Fq, Gr, Hs,will also describe cylinders that will circumscribe the cone ICE. Now, it may be demonstrated, as was done of the prisms inscribed in a pyramid (13. 3. Sup.), that the sum of all the cylinders described within the hemisphere, is exceeded by the hemisphere by a solid less than the cylinder I. E generated by the rectangle HB, that is, by a solid less than W, for the cylinder generated by HB is less than . In the same manner, it may be demonstrated, that the sum of the cylinders circumscribing the cone ICE is greater than the cone by a solid less than the cylinder generated by the rectangle DN, that is, by a solid less than W. Therefore, since the sum of the cylinders inscribed in the hemisphere, together with a solid less than W, is equal to the hemisphere; and, since the sum of the cylinders described about the cone is equal to the cone together with a solid less than W; adding equals to equals ; the sum of all these cylinders, togetber with a solid less than W, is equal to the sum of the hemispbere and the cone together with a solid less than W. Therefore, the difference between the wbole of the cylinders and the sum of the hemispbere and the cone, is equal to the difference of two solids, which are each of them less than W; but this difference must also be less than W, therefore the difference between the two series of cylinders and the sum of the hemisphere and cone is less than the given solid W. Q. E. D. PROP, XX. a The same things being supposed as in the last proposition, the sum of all the cylinders inscribed in the hemisphere, and described about the cone, is equal to a cylinder, having the same base and altitude with the hemisphere. Let the figure DCB be constructed as before, and supposed to re. volve about CD ; the cylinders inscribed in the hemisphere, that is, the cyligders described by the revolution of the rectangles Hb,Gg.Ff, together with those described about the cone, that is, the cylinders described by the revolution of the rectangles Hs, Gr, F4, and DN are equal to the cylinder described by the revolution of the rectangle DB. Let L be the point in which GO meets the circle ADB,then, because CGL is a right angle if CL be joined, the circles described with the distances CG and GL are equal to the circle described with the distance CL (2. Cor. 6. 1. Sup.) or GO ; now, CG is equal to GR, because CD is equal to DE, and therefore also, the circles described with the distances ĠR and GL are together equal to the circle described with the distance GO, that is, the circles described by the revolution of GR and GL about the point G, are together equal to the circle described by the revolution of GO about the same point G; therefore also, the cylinders that stand upon the two first of these circles having the common altitudes GH, are equal to the cylinder which stands on the remaining circle, and which has the same altitude GH. The cy. linders described by the revolution of the rectangles Gg, and Gr are therefore equal to the cylinder described by the rectangle GP. And as the same may be shewn of all the rest, therefore the cylinders described by the rectangles Hh, Gg, Ff, and by the rectangles Hs, Gr, Еe Fq, DN, are together equal to the cylinder described by DB, that is, to the cylinder having the same base and altitude with the hemisphere Q. E. D. PROP. XXI. Every sphere e's two-thirds of the circumscribing cylinder. Let the figure be constructed as in the two last propositions, and if the hemisphere described by BDC be not equal to two-thirds of the cylinder described by BD, let it be greater by the solid W. Then, as the cone described by CDE is one-third of the cylinder (18.3.Sup.) described by BD, the cone and the hemisphere together will exceed D E B ; hl A C I the cylinder by W. But that cylinder is equal to the sum of all the cylinders described by the rectangles Hh, Gg, Ff, Hs, Gr, Fq, DN (20. 3. Sup.); therefore the hemisphere and the cone added together exceed the sum of all these cylinders by the given solid W; which V is absurd, for it has been shewn (19. 3. Sup.), that the hemisphere and the cone together differ from the sum of the eylinders by a solid less than W. The hemisphere is therefore equal to two-thirds of the cylinder described by the rectangle BD; and therefore the whole sphere is equal to two-thirds of the cylinder described by twice the rectangle BD, that is, to two-thirds of the circumscribing cylinder. QE. D. END OE THE SUPPLEMENT TO THE ELEMENTS |