Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids ; to which are Added Elements of Plane and Spherical Trigonometry |
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Página 24
... AC be produced to D and E , the angle ABC shall be equal to the angle ACB , and the angle CBD to the angle BCE . In BD take any point F , and from AE the greater cut off AG equal ( 3. 1. ) to AF , the less , and join FC , GB .
... AC be produced to D and E , the angle ABC shall be equal to the angle ACB , and the angle CBD to the angle BCE . In BD take any point F , and from AE the greater cut off AG equal ( 3. 1. ) to AF , the less , and join FC , GB .
Página 25
off DB equal to AC the less , and join DC ; therefore , beΑ . cause in the triangles DBC , ACB , DB is equal to AC , and BC common to both , the two sides DB , BC are equal to the two AC , D CB , each to each ; but the angle DBC is also ...
off DB equal to AC the less , and join DC ; therefore , beΑ . cause in the triangles DBC , ACB , DB is equal to AC , and BC common to both , the two sides DB , BC are equal to the two AC , D CB , each to each ; but the angle DBC is also ...
Página 26
Join CD , and if possible let CB be equal to DB ; then , in the case D in which the vertex of each of the triangles is without the other triangle , because AC is equal to AD , the angle ACD is equal ( 5. 1. ) to the angle ADC : But the ...
Join CD , and if possible let CB be equal to DB ; then , in the case D in which the vertex of each of the triangles is without the other triangle , because AC is equal to AD , the angle ACD is equal ( 5. 1. ) to the angle ADC : But the ...
Página 27
off AE equal to AD ; join DE , and upon it describe A ( 1. 1. ) an equilateral triangle DEF ; then join AF ; the straight line AF bisects the angle BAC . Because AD is equal to AE , and AF is common to the two triangles DAF , EAF ; the ...
off AE equal to AD ; join DE , and upon it describe A ( 1. 1. ) an equilateral triangle DEF ; then join AF ; the straight line AF bisects the angle BAC . Because AD is equal to AE , and AF is common to the two triangles DAF , EAF ; the ...
Página 28
the F equilateral triangle DFE , and join FC ; the straight line FC , drawn from the given point C , is at right angles to the given straight line AB , Because DC is equal to CE , and FC common to the two tri .
the F equilateral triangle DFE , and join FC ; the straight line FC , drawn from the given point C , is at right angles to the given straight line AB , Because DC is equal to CE , and FC common to the two tri .
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ABC is equal ABCD altitude angle ABC angle BAC arch base bisected Book called centre circle circle ABC circumference coincide common cylinder definition demonstrated described diameter difference divided double draw drawn equal equal angles equiangular Euclid exterior angle extremity fall fore four fourth given given straight line greater half inscribed interior join less Let ABC magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism produced PROP proportionals proposition proved radius ratio reason rectangle contained rectilineal figure right angles segment shewn sides similar sine solid square straight line taken tangent THEOR thing third touches triangle ABC wherefore whole