Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids ; to which are Added Elements of Plane and Spherical Trigonometry |
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Página 18
... a perpendicular to it . " M JE 인 VIII . An obtuse angle is that which is greater than a right angle . IX . An acute angle is that which is less than a right angle : X. A figure is that which is inclosed by one or more boundaries .
... a perpendicular to it . " M JE 인 VIII . An obtuse angle is that which is greater than a right angle . IX . An acute angle is that which is less than a right angle : X. A figure is that which is inclosed by one or more boundaries .
Página 29
To draw a straight line perpendicular to a given straight line , of an unlimited length , from a given point without it . Let AB be a given straight line , which may be produced to any length both ways , and let C be a point without it ...
To draw a straight line perpendicular to a given straight line , of an unlimited length , from a given point without it . Let AB be a given straight line , which may be produced to any length both ways , and let C be a point without it ...
Página 62
In obtuse angled triangles , if a perpendicular be drawn from any of the acute angles to the opposite side produced , the square of the side subtending the obtuse angle is greater than the squares of the sides containing the obtuse ...
In obtuse angled triangles , if a perpendicular be drawn from any of the acute angles to the opposite side produced , the square of the side subtending the obtuse angle is greater than the squares of the sides containing the obtuse ...
Página 63
Lastly , Let the side AC be perpendicular to BC ; then is BC the straight Α . line between the perpendicular and the acute angle at B ; and it is manifest that ( 47. 1. ) ABS + BC = AC + 2BC = AC2 + 2BC.BC . Therefore in every triangle ...
Lastly , Let the side AC be perpendicular to BC ; then is BC the straight Α . line between the perpendicular and the acute angle at B ; and it is manifest that ( 47. 1. ) ABS + BC = AC + 2BC = AC2 + 2BC.BC . Therefore in every triangle ...
Página 64
Let ABC be a triangle , of which the side BC is bisected in D , and DA drawn to the opposite angle ; the squares of BA and AC are together double of the squares of BD and DA . From A draw AE perpendicular to BC , and because BEA is a ...
Let ABC be a triangle , of which the side BC is bisected in D , and DA drawn to the opposite angle ; the squares of BA and AC are together double of the squares of BD and DA . From A draw AE perpendicular to BC , and because BEA is a ...
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ABC is equal ABCD altitude angle ABC angle BAC arch base bisected Book called centre circle circle ABC circumference coincide common cylinder definition demonstrated described diameter difference divided double draw drawn equal equal angles equiangular Euclid exterior angle extremity fall fore four fourth given given straight line greater half inscribed interior join less Let ABC magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism produced PROP proportionals proposition proved radius ratio reason rectangle contained rectilineal figure right angles segment shewn sides similar sine solid square straight line taken tangent THEOR thing third touches triangle ABC wherefore whole