Elements of Geometry: Containing the First Six Books of Euclid, with a Supplement on the Quadrature of the Circle and the Geometry of Solids ; to which are Added Elements of Plane and Spherical Trigonometry |
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Página 44
et деta > 1 : HE OSC but the triangle ABC is the half of the parallelogram EBCA , because the diameter AB bisects ( 34. 1. ) it ; and the triangle DBC is the half of the parallelogram DBCF , because the diameter DC bisects it ; and the ...
et деta > 1 : HE OSC but the triangle ABC is the half of the parallelogram EBCA , because the diameter AB bisects ( 34. 1. ) it ; and the triangle DBC is the half of the parallelogram DBCF , because the diameter DC bisects it ; and the ...
Página 45
... shall be equal to a given triangle , and have one of its angles equal to a given rectilineal angle Let ABC be the given triangle , and D the given rectilineal angle . > : but the triangle ABC is the half of OF GEOMETRY . BOOK 1 .
... shall be equal to a given triangle , and have one of its angles equal to a given rectilineal angle Let ABC be the given triangle , and D the given rectilineal angle . > : but the triangle ABC is the half of OF GEOMETRY . BOOK 1 .
Página 46
but the triangle ABC is the half of the parallelogram EBCA , because the diameter AB bisects ( 34. 1. ) it ; and the triangle DBC is the half of the parallelogram DBCF , because the diameter DC bisects it ; and the halves of equal ...
but the triangle ABC is the half of the parallelogram EBCA , because the diameter AB bisects ( 34. 1. ) it ; and the triangle DBC is the half of the parallelogram DBCF , because the diameter DC bisects it ; and the halves of equal ...
Página 56
... is equal to the square of half the line . Let the straight line AB be divided into two equal parts in the point C , and into two unequal parts in the point D ; the rectangle AD.DB , D together with the square of CD , is equal to the ...
... is equal to the square of half the line . Let the straight line AB be divided into two equal parts in the point C , and into two unequal parts in the point D ; the rectangle AD.DB , D together with the square of CD , is equal to the ...
Página 59
From the demonstration it is manifest , that since the “ square of CD is quadruple of the square of CB , the square of any “ line is quadruple of the square of half that line . ” Otherwise : * Because AD is divided any how in C ( 4. 2. ) ...
From the demonstration it is manifest , that since the “ square of CD is quadruple of the square of CB , the square of any “ line is quadruple of the square of half that line . ” Otherwise : * Because AD is divided any how in C ( 4. 2. ) ...
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ABC is equal ABCD altitude angle ABC angle BAC arch base bisected Book called centre circle circle ABC circumference coincide common cylinder definition demonstrated described diameter difference divided double draw drawn equal equal angles equiangular Euclid exterior angle extremity fall fore four fourth given given straight line greater half inscribed interior join less Let ABC magnitudes manner meet multiple opposite parallel parallelogram pass perpendicular plane polygon prism produced PROP proportionals proposition proved radius ratio reason rectangle contained rectilineal figure right angles segment shewn sides similar sine solid square straight line taken tangent THEOR thing third touches triangle ABC wherefore whole