2. The parallel sides of a trapezoid are 12.41 and 8.22 chains, and their perpendicular distance 5.15 chains: required the area. Ans. 5A. IR. 10P. 3. Required the area of a trapezoid whose parallel sides are 11.34 and 18.46 chains, and their perpendicular distances 13.25 chains. Ans. 19A, 2R. 39P. PROBLEM X. To find the area of a circle, or of an ellipsis. * RULE, Multiply the square of the circle’s diameter, or the product of the two diameters of the ellipsis, by .7854, for the area.t Note. l. If the diameter of a circle be multiplied by 3.1416, the product will be the circumference; also if the circumference be divided by 3.1416, the quotient will be the diameter. 2. If the area of a circle be divided by .7854, the square root of the quotient will be the diameter. * If two pins be set upright in a plane, and a thread, the length of which is greater than twice the distance between the pins, having the ends tied together be put about the pins; and if the point of a pin or pencil, applied to the thread, and held so as to keep it uniformly tense, be moved round, till it return to the place from which the motion began; then the point of the pin or pencil will have described on the plane, a curved line called an Ellipsis. † The demonstration of this rule is too abstruse to admit of a place in this work. The student who wishes to see a demonstration is referred to treatises on Mensuration or Fluxions. EXAMPLES. 1. How many acres are in a circle a mile in diameter? a 1 mile = 80 Ch. 80 6400 .7854 3141600 47124 5026.5600 Sq. Ch. = 502A. 2R. 25P. nearly. Or by logarithms. S 80 log. 1.90309 1.90309 .7854 1.89509 { 5026.56 Sq. Ch. 3.70127 2. Required the area of an ellipsis, the longer diameter of which measures 5.36 Ch, and the shorter 3.28 Ch. Ch. 5.36 3.28 3. Required the area of a circular park, the diameter of which is 100 perches. Ans. 49A. OR. 14P. 4. Required the area of an elliptical fish pond, the longer diameter of which is 10 perches, and the shorter 5 perches. Ans. 39.27 Sq. Per. PROBLEM XI. To protract a Survey, and to find its area by dividing it into triangles and trapeziums. The method of doing this will be best understood by an example. Thus, Suppose the following field-notes to be given, it is required to protract the survey and find its area. To protract the survey. Method Ist. ginning, and apply the straight edge of the protractor to the line, with the centre to the point A, and the arch turned toward the east, because the first bearing is easterly; then holding the protractor in this position, prick off 50° the first bearing, from the north end, because the bearing is from the north ; through this point and the ; point A, draw the line AB on which lay 9.60 chains, the first distance from A to B. Now apply the centre of the protractor to the point B, with the arch turned toward the east, because the second bearing is easterly, and move it till the line AB produced cuts the first bearing 50°; the straight edge of the protractor will then be parallel to the meridian NS; hold it in this position, and from the south end prick off the second bearing 32°; draw BC and on it lay the second distance 16.38 chains. Proceed in the same manner at each station, observing al. ways, previous to pricking off the succeeding bearing, to have the arch of the protractor turned easterly or westerly according to that bearing, and to have its straight edge parallel to the meridian ; this last may always be done by applying the centre to the station point, and making the preceding distance line, produced if necessary, cut the degrees of the preceding bearing: also be done by drawing a straight line through each station, parallel to the first meridian. When the survey is correct and the protraction accurately performed, the end of the last distance will fall on It may Method second. With the chord of 60° describe the circle NESW, Fig. 76, and draw the diameter NS. Take the several bearings from the line of chords, and lay them off on the circumference from N or S according as the bearing is northerly or southerly, and towards E or W according as it is easterly or westerly, and number them 1, 2, 3, 4, &c. as in the figure. From A the centre of the circle, to 1 draw A l, on which lay the first distance from A to B; parallel to A 2 draw BC on which lay the second distance from B to C; parallel to A 3 draw CD on which lay the third distance from C to D; proceed in the same manner with the other bearings and distances. To find the area. By drawing lines as in Fig. 75, the survey is divided into two trapeziums AGFE, AEDB, and a triangle BDC. Measure the several bases and perpendiculars, on the same scale that was used in the protraction, and find the double areas of the triangle and trapeziums by probs. 2 and 6; the sum of these will be the double area of the survey. Bases. Perpens. = 203.6628 = 2 AGFE = 267.4215 = 2 AEDB Dd 8.10 BD 19.23 x Ce 5.16 = 99.2268 = 2 BDC 2)570.3111ch.=2ABCDEFG 285.15555ch.=28A.2R.2P. =the area required. |