A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
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Resultados 1-5 de 100
Página 110
... lat . will be 64.51Ch . S. and the dep . 45.59Ch . E .: but if the bearing and distance be S. 54 ° 45′E . dist . 79Ch . the diff . of lat . will be 45.59Ch . S. and the dep . 64.51.Ch. E. When the distance is expressed by any whole ...
... lat . will be 64.51Ch . S. and the dep . 45.59Ch . E .: but if the bearing and distance be S. 54 ° 45′E . dist . 79Ch . the diff . of lat . will be 45.59Ch . S. and the dep . 64.51.Ch. E. When the distance is expressed by any whole ...
Página 111
... Lat . 93.67 and Dep . 35.02 17 -- Whole Dist . 117 15.92 5.95 Lat . 109.59N . Dep . 40.97E . 2. What is the clifference of latitude and departure of 10 a line bearing N. 784 ° W . dist . 243 perches ? Per . Per . Per . Dist . 100 ...
... Lat . 93.67 and Dep . 35.02 17 -- Whole Dist . 117 15.92 5.95 Lat . 109.59N . Dep . 40.97E . 2. What is the clifference of latitude and departure of 10 a line bearing N. 784 ° W . dist . 243 perches ? Per . Per . Per . Dist . 100 ...
Página 112
... Lat . 42.53 and Dep . 37.96 .36 Whole Dist . 57.36 .27 .24 Lat . 42.80S . Dep . 38.20W . 2. Required the latitude and departure corresponding to a line which bears N. 72 ° W . dist . 124.37 perches . Per . Per . Per . Dist . 100.00 cor .
... Lat . 42.53 and Dep . 37.96 .36 Whole Dist . 57.36 .27 .24 Lat . 42.80S . Dep . 38.20W . 2. Required the latitude and departure corresponding to a line which bears N. 72 ° W . dist . 124.37 perches . Per . Per . Per . Dist . 100.00 cor .
Página 129
... Lat . N. 4.93 Dep . E. 5.32 Draw CD parallel to NS , and on it let fall the perpen- dicular ED ; then will CD be the difference of latitude , and ED the departure corresponding to the 3rd side , and the angle DCE will be the bearing ...
... Lat . N. 4.93 Dep . E. 5.32 Draw CD parallel to NS , and on it let fall the perpen- dicular ED ; then will CD be the difference of latitude , and ED the departure corresponding to the 3rd side , and the angle DCE will be the bearing ...
Página 132
... latitude and departure of the closing line , its ... dep . 10.64 W. 1.02694 So is rad . - 10.00000 11.02694 To tang . of bearing S. 60 ° 8 ′ W. 10.24090 To find the distance . As rad . Is to sec . of bearing 60 ° 8 ' So is diff . of lat ...
... latitude and departure of the closing line , its ... dep . 10.64 W. 1.02694 So is rad . - 10.00000 11.02694 To tang . of bearing S. 60 ° 8 ′ W. 10.24090 To find the distance . As rad . Is to sec . of bearing 60 ° 8 ' So is diff . of lat ...
Términos y frases comunes
ABCD ABFD acres adjacent adjacent angles angle ABC angle opposite angled triangle azimuth base bearing and distance breadth Calculation centre Co-secant Secant Co-sine Co-tang column decimal degrees DEMONSTRATION departure corresponding diff difference of latitude Dist divide division line draw equal EXAMPLES feet figures find the angle find the area four-pole chains fourth term given angle given area given bearing given ratio given side John Gummere Lat Dep latitude and departure length logarithm measured meridian distance natural number off-sets parallel parallelogram perches perpendicular perpendicular BC quired quotient radius rectangle remainder Required the area right angle right line right-angled triangle RULE semiperimeter side AB side AC sine square root station stationary line subtract tance Tang Tangent tract of land trapezium trapezoid triangle ABC trigonometry