A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
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Página 9
Logarithms , 9 Geometrical Definitions , 26 Geometrical Problems , 36 Plane Trigonometry , 35 Application of Plane Trigonometry to the Mensuration of Distances and Heights , 68 Practical Questions , 78 Measuring Land , 81 Preliminary ...
Logarithms , 9 Geometrical Definitions , 26 Geometrical Problems , 36 Plane Trigonometry , 35 Application of Plane Trigonometry to the Mensuration of Distances and Heights , 68 Practical Questions , 78 Measuring Land , 81 Preliminary ...
Página 68
The following examples , in which trigonometry is applied to the mensuration of inaccessible distances and heights , will serve to render the student expert in solving the different cases , and also to elucidate its use .
The following examples , in which trigonometry is applied to the mensuration of inaccessible distances and heights , will serve to render the student expert in solving the different cases , and also to elucidate its use .
Página 74
Wishing to know the height of a steeple situated on a horizontal plane , I measured 100 feet in a right line from its base , and then took the angle of elevation * of the top , which I found to be 47 ° 30 ' , the centre of the quadrant ...
Wishing to know the height of a steeple situated on a horizontal plane , I measured 100 feet in a right line from its base , and then took the angle of elevation * of the top , which I found to be 47 ° 30 ' , the centre of the quadrant ...
Página 75
In the right - angled triangle DEC , we have the angle CDE = 47 ° 30 ' and the base DE = AB = 100 feet to find CE = 109.13 feet ; to CE add EB = DA = 5 feet the height of the quadrant , and it will give BC = 114.13 feet , the required ...
In the right - angled triangle DEC , we have the angle CDE = 47 ° 30 ' and the base DE = AB = 100 feet to find CE = 109.13 feet ; to CE add EB = DA = 5 feet the height of the quadrant , and it will give BC = 114.13 feet , the required ...
Página 76
CDE = BDC - BDE = 16 ° 50 , DCE = 90 ° — ' = 90 ° — BDC 22 ° 10 ' , DEC = 180 ° — the sum of the angles CDE and DCE , = 141 ° , and CD = 230.4 , to find CE = 106 yards , the height of the tower . 3. In the right angled triangle DBC ...
CDE = BDC - BDE = 16 ° 50 , DCE = 90 ° — ' = 90 ° — BDC 22 ° 10 ' , DEC = 180 ° — the sum of the angles CDE and DCE , = 141 ° , and CD = 230.4 , to find CE = 106 yards , the height of the tower . 3. In the right angled triangle DBC ...
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ABCD according acres adjacent angle base bearing bearing and distance Calculation called centre circle Co-secant Co-sine Co-tang column Construction contained corresponding Courses decimal Deg Dist DEMONSTRATION describe difference distance divide division draw east equal EXAMPLES feet figures find the area given given angle given area given side greater half hand height hypothenuse join latitude and departure length less logarithm measured meeting meridian distance Note off-sets opposite parallel perches perpendicular preceding PROBLEM quotient radius ratio rectangle remainder Required the area right angle right line root RULE running scale Secant side side AC sine square station subtract survey taken Tang Tangent triangle ABC twice