A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
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Thus ADC and BDC are right angles , and the line CD is perpendicular to AB , Fig . 4 . 10. An acute angle is that which is less than a right angle , as BDE , Fig . 4 . 11. An obtuse angle is that which is greater than a right angle ...
Thus ADC and BDC are right angles , and the line CD is perpendicular to AB , Fig . 4 . 10. An acute angle is that which is less than a right angle , as BDE , Fig . 4 . 11. An obtuse angle is that which is greater than a right angle ...
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That side upon which any parallelogram , or trian- . gle is supposed to stand , is called the base ; and the perpendicular falling thereon from the opposite angle is called the altitude of the parallelogram , or triangle . GEOMETRY .
That side upon which any parallelogram , or trian- . gle is supposed to stand , is called the base ; and the perpendicular falling thereon from the opposite angle is called the altitude of the parallelogram , or triangle . GEOMETRY .
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tances AC , AD ; from C and D , as centres , with any radius greater than AC or AD , describe two arcs intersecting each other in B ; from A to B , draw the line AB , which will be the perpendicular required . PROBLEM III .
tances AC , AD ; from C and D , as centres , with any radius greater than AC or AD , describe two arcs intersecting each other in B ; from A to B , draw the line AB , which will be the perpendicular required . PROBLEM III .
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At the end B of the line AB , by problem 3 , erect the perpendicular BC , and make it equal to AB ; with A and C as centres , and distance AB or BC describe two arcs cutting each other in D ; draw AD and CD GEOMETRICAL PROBLEMS . 31.
At the end B of the line AB , by problem 3 , erect the perpendicular BC , and make it equal to AB ; with A and C as centres , and distance AB or BC describe two arcs cutting each other in D ; draw AD and CD GEOMETRICAL PROBLEMS . 31.
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... and DE equal B ; bisect CE in F , and with the B centre F and radius FC or FE describe the semicircle CGE ; draw DG perpendicular to CE : then DG will be a mean propor . tional between A and B. с D E 2 PROBLEM XVI .
... and DE equal B ; bisect CE in F , and with the B centre F and radius FC or FE describe the semicircle CGE ; draw DG perpendicular to CE : then DG will be a mean propor . tional between A and B. с D E 2 PROBLEM XVI .
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Términos y frases comunes
ABCD according acres adjacent angle base bearing bearing and distance Calculation called centre circle Co-secant Co-sine Co-tang column Construction contained corresponding Courses decimal Deg Dist DEMONSTRATION describe difference distance divide division draw east equal EXAMPLES feet figures find the area given given angle given area given side greater half hand height hypothenuse join latitude and departure length less logarithm measured meeting meridian distance Note off-sets opposite parallel perches perpendicular preceding PROBLEM quotient radius ratio rectangle remainder Required the area right angle right line root RULE running scale Secant side side AC sine square station subtract survey taken Tang Tangent triangle ABC twice