A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
Dentro del libro
Resultados 1-5 de 18
Página 27
A parallelogram , whose angles are all right angles , is called a rectangle , as E , Fig . 12 . 25. A parallelogram whose sides are all equal , and angles right , is called a square as F , Fig . 13 . 26. A rhomboides is a parallelogram ...
A parallelogram , whose angles are all right angles , is called a rectangle , as E , Fig . 12 . 25. A parallelogram whose sides are all equal , and angles right , is called a square as F , Fig . 13 . 26. A rhomboides is a parallelogram ...
Página 86
PROBLEM I. To find the Area of a Parallelogram , whether it be a a Square , a Rectangle , a Rhombus , or a Rhomboides . RULE . Multiply the length by the height or perpendicular breadth , and the product will be the area . * Note .
PROBLEM I. To find the Area of a Parallelogram , whether it be a a Square , a Rectangle , a Rhombus , or a Rhomboides . RULE . Multiply the length by the height or perpendicular breadth , and the product will be the area . * Note .
Página 90
As radius , Is to the sine of the included angle ; So is the rectangle of the given sides , To double the area . * EXAMPLES , 1. In a triangular lot of ground ABC , the side AB measures 64 perches , the side AC 40.5 perches , and their ...
As radius , Is to the sine of the included angle ; So is the rectangle of the given sides , To double the area . * EXAMPLES , 1. In a triangular lot of ground ABC , the side AB measures 64 perches , the side AC 40.5 perches , and their ...
Página 91
... As the rectangle of radius and the sine of the angle opposite the given side , Is to the rectangle of the sines of the other angles , So is the square of the given side , To double the area . * . * DEMONSTRATION . Let AB , Fig .
... As the rectangle of radius and the sine of the angle opposite the given side , Is to the rectangle of the sines of the other angles , So is the square of the given side , To double the area . * . * DEMONSTRATION . Let AB , Fig .
Página 93
No ; hence ( 22.6 ) M : DG :: AH : N ; consequently the rectangle Mx N is equal to the rectangle AH X DG ; therefore ABC ABG + BCG + ACG AH X DG MXN = V ( AD X BD ) XV ( AH X HB ) = V ( AB X BD X HB X AH ) . The angle BAC is less than ...
No ; hence ( 22.6 ) M : DG :: AH : N ; consequently the rectangle Mx N is equal to the rectangle AH X DG ; therefore ABC ABG + BCG + ACG AH X DG MXN = V ( AD X BD ) XV ( AH X HB ) = V ( AB X BD X HB X AH ) . The angle BAC is less than ...
Comentarios de la gente - Escribir un comentario
No encontramos ningún comentario en los lugares habituales.
Términos y frases comunes
ABCD according acres adjacent angle base bearing bearing and distance Calculation called centre circle Co-secant Co-sine Co-tang column Construction contained corresponding Courses decimal Deg Dist DEMONSTRATION describe difference distance divide division draw east equal EXAMPLES feet figures find the area given given angle given area given side greater half hand height hypothenuse join latitude and departure length less logarithm measured meeting meridian distance Note off-sets opposite parallel perches perpendicular preceding PROBLEM quotient radius ratio rectangle remainder Required the area right angle right line root RULE running scale Secant side side AC sine square station subtract survey taken Tang Tangent triangle ABC twice