A Treatise on Surveying,: Containing the Theory and Practice: : to which is Prefixed a Perspicuous System of Plane Trigonometry. : The Whole Clearly Demonstrated and Illustrated by a Large Number of Appropriate Examples. : Particularly Adapted to the Use of SchoolsKimber and Sharpless, no. 93, Market Street, and John Richardson, no. 244, Market Street., 1820 - 206 páginas |
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Página 26
... triangle is a figure bounded by three straight lines , as ABC , Fig . 6 . 15. An equilateral triangle has its three sides equal to each other , as A , Fig . 7 . 16. An isosceles triangle has only two of its sides equal , as B , Fig . 8 ...
... triangle is a figure bounded by three straight lines , as ABC , Fig . 6 . 15. An equilateral triangle has its three sides equal to each other , as A , Fig . 7 . 16. An isosceles triangle has only two of its sides equal , as B , Fig . 8 ...
Página 27
... triangle has one obtuse angle , as C , Fig . 10 . 20. An acute angled triangle has all its angles acute , as ABC , Fig . 6 . 21. Acute and obtuse angled triangles are called oblique angled triangles . 22. Any plane figure bounded by ...
... triangle has one obtuse angle , as C , Fig . 10 . 20. An acute angled triangle has all its angles acute , as ABC , Fig . 6 . 21. Acute and obtuse angled triangles are called oblique angled triangles . 22. Any plane figure bounded by ...
Página 28
... triangle . Thus AD is the base of the parallelogram ABEC , or triangle ABC , and CD is the altitude . Fig . 15 . 1 32. All plane figures contained under more than four sides , are called polygons ; of which those having five sides , are ...
... triangle . Thus AD is the base of the parallelogram ABEC , or triangle ABC , and CD is the altitude . Fig . 15 . 1 32. All plane figures contained under more than four sides , are called polygons ; of which those having five sides , are ...
Página 31
... ABC is the triangle required . PROBLEM IX . Upon a given line AB to describe a square , Fig . 26 . At the end B of the line AB , by problem 3 , erect the perpendicular BC , and make it equal to AB ; with A and cutting each other in D ...
... ABC is the triangle required . PROBLEM IX . Upon a given line AB to describe a square , Fig . 26 . At the end B of the line AB , by problem 3 , erect the perpendicular BC , and make it equal to AB ; with A and cutting each other in D ...
Página 32
... triangle ABC , Fig . 27 . By problem 1 , bisect any two of the sides , as AC , BC , by the perpendiculars DE and FG ; the point H where they intersect each other will be the centre of the circle ; with this centre , and the distance ...
... triangle ABC , Fig . 27 . By problem 1 , bisect any two of the sides , as AC , BC , by the perpendiculars DE and FG ; the point H where they intersect each other will be the centre of the circle ; with this centre , and the distance ...
Términos y frases comunes
ABCD ABFD acres adjacent adjacent angles angle ABC angle opposite angled triangle base bearing and distance breadth Calculation centre Co-secant Secant Co-sine Co-tang column cube root decimal DEMONSTRATION departure corresponding diff difference of latitude Dist divide division line draw equal EXAMPLES feet figures find the angle find the area four-pole chains fourth term given angle given area given bearing given number given ratio given side John Gummere Lat Dep latitude and departure length logarithm M.
M. Sine measured meridian distance natural number off-sets parallel parallelogram perches perpendicular quired quotient radius rectangle remainder Required the area right angle right line right-angled triangle RULE semiperimeter side AB side AC square root station stationary line subtract survey tance Tang tangent tract of land trapezium trapezoid triangle ABC trigonometry