Imágenes de páginas
PDF
EPUB

Cor. The areas of the colunar triangles are

(2A - E) (2 B — E) π2,

180°

220. Problem.

[ocr errors]

given the three sides.

180°

(2 C — E) πr2.

180°

To find the area of a triangle, having

Here the object is to express E in terms of the sides.

I. Cagnoli's Theorem.

[ocr errors]

sin Esin (A+B+C − π)

=sin(A+B) sin C-cos (A+B) cos C

sin C cos C [cos (a - b) — cos (a+b)] . (Art. 198)

cos c

[merged small][merged small][merged small][merged small][ocr errors][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small]

=

[merged small][merged small][merged small][merged small][merged small][ocr errors][merged small]

= √tan s tan 1 (s—a) tan 1⁄2 (s—b) tan (s—c) (Art. 195) (3)

221. Problem. To find the area of a triangle, having

given two sides and the included angle.

cos Ecos [(A + B) − († π − † C)]

= cos(A + B) sin + C + sin (A+B) cos C

= cos(a+b) sin2C+cos(a-b) cos2C (Art. 198)

= [cosa cos b+sina sin b cos C] secc

=

[ocr errors]

(1) Dividing (1) of Art. 220 by this equation, and reducing,

we have

[merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][ocr errors][merged small][merged small][ocr errors][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small]

2.

find

3.

find

4.

find

75°33';

Given A 84°20'19", B = 27° 22' 40", C= 75° 33';

E=7°15' 59".

Given a 46° 24', b = 67° 14', c = 81°12';

=

[blocks in formation]

Given a 108° 14', b = 75° 29', c = 56° 37';
E = 48° 32' 34".5.

1+ cos a + cos b + cos c

5. Prove cos E =

[blocks in formation]

4 cosa cosb cos c

cos2a + cos2b+cos2 c-1.

2 cosa cosb cos c

sinssin (s-a) sin (s—b) sin(s—c). cosa cosb cosc.

cos scos (s-a) cos 1⁄2 (s—b) cos (s—c). cosa cosb cos c

cota cot b+cos C

sin C

cot bcotc+cos A

sin A

cotic cota + cos B
sin B

7.

66 cos E=

8.

"cot E

=

EXAMPLES.

Prove the following:

1. sin(sa) + sin (s — b) + sin(s — c) — sins

= 4 sina sinb sinc.

2. sins + sin(sb) + sin(sc) sin (sa)

[blocks in formation]

3. sin(sb) sin (s — c) + sin(s — c) sin (s — a)

+sin(sa) sin (sb) + sin s sin (sa) sins sin (sb) + sin s sin (sc)

= sin b sinc+ sinc sina + sin a sin b.

4. sin(sb) sin (s—c) + sin(sc) sin(sa)

=

sin (sa) sin (s — b) + sin s sin (s—a) sins sin (sb) sins sin(s—c)

sinb sinc+ sin c sin a sin a sin b.

5. sin's + sin(s — a) + sin2 (s — b) + sin2 (s — c)

= 2(1― cos a cos b cos c).

6. sin's + sin(s — a) — sin2 (s—b) — sin2(sc)

= 2 cos a sin b sin c.

7. cos2s+cos2 (s − a) + cos2 (s — b) + cos2 (s — c)

[blocks in formation]

8. cos2s + cos2(s — a) — cos2 (s — b) — cos2 (s — c)

[blocks in formation]

17. cot2r12+cot2r2+ cot2r; +cot2r = 2(1–cos a cos b cos ()

n2

[blocks in formation]

19. cot r2 cot r2 + cot r2 cot r1 + cot r1 cot r2

n2

+cot r(cot r+cot r2+cot rs) sin b sin c + sin e sin a + sin a sin b n2

20. tan r2 tan r2+ tan r tan r1 + tan r1 tan r2

[blocks in formation]

25. tan R1+tan R2+ tan R tan R = 2 cot r.

2

26. tan R tan R1 + tan R2+ tan R2 = 2 cot 11.

3

27. tan R+ tan R1 tan R2+tan R = 2 cot 12.

28. tan R+tan R1 + tan R2 tan R3 = 2 cot îo.

[ocr errors]
[merged small][merged small][ocr errors][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small][merged small]

33. tan R+cot r = tan R1 + cot r1 = etc.,

= 1⁄2 (cot r + cot r1 + cot r2+ cot r3).

=

34. tan2 R+tan2 R1 + tan2 R2 + tan2 R3

2(1+cos A cos B cos C) N2

« AnteriorContinuar »