 | 1801 - 658 páginas
...2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A ABD+ A BCD, or , , , ABxDE , DCxDE the... | |
 | James Thompson - 1808 - 176 páginas
...IV. To find the area of a trafiezoid, or quadrangle, <u'o cf •whose opposite sides are parallel. RULE — Multiply the sum of the parallel sides by...between them, and half the product •will be the area. EXAMPLES. 13. Required the area of a trapezoid whose parallel sidef »re 25 feel 6 inches, and 18 feet... | |
 | Peter Nicholson - 1809 - 426 páginas
...BF. 14 X36 84 42 504=the area of ABCD. PROBLEM VI. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. EXAMPLE I. What is fhe area of a board or plank in the form of a trapeziod,... | |
 | Matthew Iley - 1820 - 512 páginas
...Area of a Quadrilateral wherein two unequal Sides are Parallel to one another. RULE. Multiply half the sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Let ABCD be a quadrilateral, wherein AC and BD are parallel but unequal;... | |
 | Anthony Nesbit, W. Little - 1822 - 916 páginas
...bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area in square inches. Divide this area by 2 82, 231, and 2150.42, and the respective quotients will be... | |
 | John Nicholson - 1825 - 838 páginas
...been subtracted. 63 I 189 3 1 189 Prot. 4. To find the Area ofaTrapezoid. Multiply the sum of the two parallel sides by the perpendicular distance between them, and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12, and the perpendicular distance AP or CN... | |
 | Peter Nicholson - 1825 - 1046 páginas
...42 501 = the arca of ABCD. MENSURATION. Prob. 6. To find the area of a trapezoid. Multiply the half sum of the parallel sides by the perpendicular distance between them, and the product will be the area. Ex. 3. What is the area of a board or plank in the form of a trapezoid,... | |
 | Thomas Hornby (land surveyor.) - 1827 - 318 páginas
...• • 00000000 2.40000 40 16.00000 Ans. 0A. 2n. 16p. PROBLEM 3. To find the Area of a Trapezoid. RULE. Multiply the sum of the parallel sides by the...between them, and half the product will be the area. EXAMPLE. Required the area of the trapezoid AB CD, whose parallel sides AB and DC are 800 and 640 links... | |
 | John Bonnycastle - 1829 - 256 páginas
...PROBLEM VI. To find the area of a trapezoid, or a quadrangle, two of whose opposite sides are parallel. RULE.* Multiply the sum of the parallel sides by the...distance between them, and half the product will be the EXAMPLES. 1. Required the area of the trapezoid ABCD, whose sides AB and DC are 321.51 and 214.24,... | |
 | Edinburgh encyclopaedia - 1830 - 856 páginas
...trapezoid. Note. A trapezoid is a quadrilateral, of which two opposite sides are parallel but not equal. RULE. Multiply the sum of the parallel sides by the...perpendicular distance between them, and half the product is the area. In the trapezoid ABCD, draw the diagonal AC, and from its extremities draw AE, CF at right... | |
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RULE.* Multiply the sum of the parallel sides by the perpendicular distance between them, and half the product will be the area. 
