 | Thomas Keith - 1817 - 306 páginas
...are contained therein? ' , Ant. 92'348l6 feet. PROBLEM IX. To fold the Solidity of a Wedge. ROLE*'. To twice the length of the base, add the length of the edge; multiply the sum by the breadth * Dtmmttrattm. Let AB CD x F represent a wedge : now, when the length of the edge c D is equal to the... | |
 | Anthony Nesbit - 1824 - 476 páginas
...receive that name until the fifteenth century. PROBLEM IX. Tojind the solidity of a cuneus or wedge. RULE. To twice the length of the base, add the length...edge, multiply the sum by the breadth of the base, and this product by the perpendicular height of the wedge ; and £ of the last product will be the solidity.... | |
 | Ireland commissioners of nat. educ - 1834 - 370 páginas
...perpendicular to the plane AC, the wedge is of the common kind ; CG is its edge, and ARBO its back. RULE II. To twice the length of the base, add the length of...edge, multiply the sum by the breadth of the base, and the product by the height of the wedge, and -| of the last product will be the solidity ; that is,... | |
 | Adrien Marie Legendre - 1836 - 394 páginas
...prismoid is the perpendicular distance between its bases. , PROBLEM VII. To find the solidity of a wedge. RULE. — To twice the length of the base add the length of the edge. Multiply this sum by the breadth of the base, and then by the altitude of the wedge, and take one-sixth of the... | |
 | Commissioners of National Education in Ireland - 1837 - 290 páginas
...perpendicular to the plane AC, the wedge is of the common kind ; CG is its edge, and ARBO to beck. RULE II. To twice the length of the base, add the length of...edge, multiply the sum by the breadth of the base, and the product by the height of the wedge, and ^ of the last product will be the solidity, that is, (2... | |
 | Thomas Holliday - 1838 - 404 páginas
...breadth of the base, perpendicular height, and the length of the edge, for the solidity. Rule.—To twice the length of the base, add the length of the...edge, multiply the sum by the breadth of the base, and this product by the perpendicular height of the wedge, and onesixth of the last product will be the... | |
 | Adrien Marie Legendre - 1839 - 372 páginas
...the perpendicular distance between its bases. PROBLEM VII. To find the solidity of a wedge. ROLE. — To twice the length of the base add the length of the edge. Multiply this sum by the. breadth of the base, and then by the altitude of the wedge, and take one-sixth of... | |
 | William Templeton (engineer.) - 1845 - 210 páginas
...depth = 95-8188 cubic feet, and x 6-232 = 597-1427 gallons. To find the solid contents of a wedge. Rule. — To twice the length of the base add the...; multiply the sum by the breadth of the base, and by the perpendicular height from the base, and one-sixth of the product is the solid contents. Application... | |
 | James Robinson (of Boston.) - 1847 - 304 páginas
...which we live, supposing the diameter to be 7912 miles? Al't. 987". To FIND THE SOLIDITY OF A WEDGE. RULE. To twice the length of the base add the length...edge; multiply the sum by the breadth of the base, and the product by one sixth of the perpendicular from the edge upon the base ; this product will be the... | |
 | 1847 - 190 páginas
...depth = 95-8l88 cubic feet, and X 6-232 = 597-1427 gallonsTo Jind the solid contents of a wedgeRule — To twice the length of the base add the length of...; multiply the sum by the breadth of the base, and by the perpendicular height from the base, and one sixth of the product is the solid contentsApplication... | |
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RULE. To twice the length of the base, add the length of the edge, multiply the sum by the breadth of the base, and this product by the perpendicular height of the wedge ; and | of the last product will be the solidity. 
