3. Find the value of - ab÷2(c2+d+e2) — a2 (b2-d+e)÷2+abc (a+c)÷2 =24÷2(4+8+0)-16 (36-8+0)÷2+48×6÷2 2424 4482288 ÷ 2 = 1-224+144 = −79 4. Find the value of 2(a3b-d2-a2c) ad + 3b (a+5cd-a3d) ÷ bab =2(384-64-32) 32+ 18 (4 x 80-128) ÷ 144 =576÷32-792÷144 18-5=121 [3a+2c-d]+2+c-[2b+c-d] ÷ 2 5. Find the value of = (12+48)2+2 (12+2-8)÷2 = 8÷2+2−6÷2=4+2−3 = 3 6. Find the value of {1+ (da) +2a} - {6a - 3b+1} 3 7. Find the value of 18+1 12 145 = 12 2×6 5 [a3+c — (4a2+b−6b2)] 8. Find the value of [(a−b) — (c–d)]2 + [(e−d2) (b+c−2d)] [(4-6) — (2−8)]2 + [(0−8×8) (6+2−2×8)] = [4]+[64x-8] 16+512=528 = |