3. Find the value of ab÷2(c2+d+e2) — a2 (b2-d+e)÷2+abc (a+c)÷2 =24÷2(4+8+0)-16 (36-8+0)2+48x6÷2 = 24 24 448÷2 + 288 ÷ 2 = 1-224+144 = -79 4. Find the value of 2(a3b-d2-a2c) ad + 3b (a+5cd-a2d) ÷ bab =2(384-64-32) ÷ 32 +18 (4 × 80—128) ÷ 144 = 576÷32 - 792÷144 = 18—51⁄2 = 12} 5. Find the value of = [3a+2c-d]+2+c-[2b+c-d]÷2 (12+48)2+2 (12+2-8)÷2 = 8÷2+2−6÷2=4+2−3 = 3 6. Find the value of = (4a2+b−6b2)] 5 [a3+c = 5 (282-70) = 5 × 212 = 1060 8. Find the value of [(a-b)-(c-d)]2 + [(e-d2) (b+c-2d)] = [(4—6) — (2-8)]2 + [(0−8×8) (6+2−2×8)] = [4]2 + [−64× −8] = 16+512 = 528 |