3. Find the value of

-

ab÷2(c2+d+e2) — a2 (b2-d+e)÷2+abc (a+c)÷2 =24÷2(4+8+0)-16 (36-8+0)÷2+48×6÷2

2424

4482288 ÷ 2

= 1-224+144 = −79

4. Find the value of

2(a3b-d2-a2c) ad + 3b (a+5cd-a3d) ÷ bab =2(384-64-32) 32+ 18 (4 x 80-128) ÷ 144

=576÷32-792÷144

18-5=121

[3a+2c-d]+2+c-[2b+c-d] ÷ 2

5. Find the value of

=

(12+48)2+2

(12+2-8)÷2

= 8÷2+2−6÷2=4+2−3 = 3

6. Find the value of

{1+ (da) +2a} - {6a - 3b+1}

3

7. Find the value of

18+1

12

145 =

12

2×6

5 [a3+c — (4a2+b−6b2)]
=5[(64+2)-(4x16+6-6×36)]
=5(282-70) = 5 x 212 = 1060

8. Find the value of

[(a−b) — (c–d)]2 + [(e−d2) (b+c−2d)] [(4-6) — (2−8)]2 + [(0−8×8) (6+2−2×8)] = [4]+[64x-8] 16+512=528

=