It will be better for the pupil at this early stage to keep the brackets till the end of the solution of the problem. When a 16, b = 12, c = 8, d= 10, e = 4, f=0 = 1. Find the value of →a, e÷b, 2÷(a+b), d÷(b+c), f÷(a+3), 4 4 2 10 = 2. Find the value of = (bcd+adf)÷ce+(b2-c2+d2)÷d+abc÷(a+b+c) [(12×8×10) + (16 × 10×0)]÷ (8×4) + [(12×12)-(8×8)+(10 × 10)] ÷ 10+ (16 × 12×8) ÷ (16+12+8) =(960+0)÷32+(144-64+100)÷10+(1536÷36) =30+18+128= 903 3. Find the value of 3 (3c-4d)÷d+(c−e÷d)÷(a+b)−(a+b+c) ÷ (a-b-c) = [(3x8)-(4×10)]÷10+(8-4+10)÷(16+12) -(16+12+8)÷(16-12-8) = (24-40) ÷ 10+14÷ 28-36--4 4. Find the value of (a2+b2)÷(2cd+f)+(c2+e2)÷2ab+(3b2—c)÷4 = [(16×16) + (12×12)] ÷ [2 (8 × Ì0) + Ó] + [(8x8)+(4x4)]÷2(16×12)+[3(12 × 12)-8]÷4 =(256+144)÷[(2 × 80)+0]+(64+16)÷(2× = +[(3x144)-8] ÷ 4 160 384 5. Find the value of 4. 4. 24 192) (10+2d2+2e3)÷ (4a-4c-2b) — (6+4d−2b) +(6d-4c) = [(10+200+128)÷8]-(22÷28) = (338÷8)—22: =2322 = 1161 = 4113 28 6. Find the value of (8ab2-c2-d2)÷(3e2 — d2)+12cd-8de = {8 [16 (12 × 12)] — (8×8) — (10×10)} ÷ [3 (4×4)-(10 × 10)] + 12 (8 × 10)—8 (10×4) (18432-64-100÷ 48-100)+960-320 = 18268 +960−320 = 28813 -52 When we wish to take the root of a quantity, this is expressed by the sign / put before the quantity. Thus 16 means square root of 16 4, or that number which multiplied by itself will make 16. So √64 is 8. /— means cube root; thus 3/5 = 2, and so on. Of course if we square a quantity first, and then take the square root of it, the quantity remains as before thus 42 is 4; √a2 is a, and so on. When a = 50, b = 32, c = 16, d 1. Find the value of = 8, e = 2, ƒ = 0. √/b2+√a2÷√d2+2√d2÷4√/a2+6√/a2÷3√b2 =b+a÷d+2d ÷ 4a+6a3b =32+50+8+ (2x8)÷(4×50)+(6 × 50)÷(3×32) =321250+16+625 200 2. Find the value of 5a5-3c4÷6+b÷c3÷d+d2÷b2xc÷8 =(5x125000)÷5--(3 × 65536)÷6+32÷4096 8+64 1024 × 16 ÷ 8 125000-65536+7836÷181×10 4096 64 8 2 1+128 = 92232 =922321 1024 3. Find the value of (a+b)÷(d2+5d) × d÷2b+4d+2c÷d+d÷b = (50+32) ÷ [(8×8)+(5×8)]×8÷(2×32)+ (4×8)+(2×16)+8+8÷32 =82×8+84 +32=8416 104 We express division sometimes without the sign ÷ by placing the divisor beneath the dividend, that is, we put the dividing number or quantity below the 16 is 16 ÷ 2 quantity or number to be divided: thus = 8. a b is ab, and so on. When a = 2 16, b= 12, c8, d= 10, e = 4, ƒ = 0. 1. Find the value of d e e 2 f a b' a+b2 b+c'ate = + (3x8)-(4×10) 8-4+10 16+12+8 + 10 16+12 16-12-8 |