| 1811 - 572 páginas
...have Sin. A. Cos. B + Cos. A. Sin. B — t- ' and Sin.c = Sin.(180* — A + B) = Sin. A + B, since the sine of an angle is equal to the sine of its supplement. Hence Sin. A + B = Sin. A. Cos. B 4- Cos. A. Sin. BQED All this is perfectly legitimate ; but how is... | |
| Miles Bland - 1819 - 442 páginas
...A e CB : CA :: sin. A : sin. B•, CA hence sin. B = ~ x sin. A, and may .-. be determined. But as the sine of an angle is equal to the sine of its supplement, the angle B may be greater or less than a right angle, unless BC be greater than AC and consequently... | |
| Miles Bland - 1819 - 444 páginas
...CB : CA :: sin. A : sin. JB; CA hence sin. U = „-£ x sin. ^/, and may .'. be determined. But as the sine of an angle is equal to the sine of its supplement, the angle B may be greater or less than a right angle, unless BC be greater than AC and consequently... | |
| Robert Gibson - 1821 - 594 páginas
...when the given angle is acute and opposite the lesser of the given sides, the answer is ambiguous, as the sine of an angle is equal to the .sine of its supplement, consequently the required angle opposite that other given side may be obtuse, or acute ; unless it... | |
| Ferdinand Rudolph Hassler - 1826 - 208 páginas
...No. l, of the series A, or first definition, we have in the two triangles, and in both cases, (since the sine of an angle is equal to the sine of its supplement.) dd — = sin С ; and — = sin В b Therefore : d = i . sin С = с . ein B Or, expressed in a proportion... | |
| Ferdinand Rudolph Hassler - 1826 - 640 páginas
...No. 1, of the series A, or first definition, we have in the two triangles, and in both cases, (since the sine of an angle is equal to the sine of its supplement.) dd — = sin C ; and — = sin B bc Therefore : d = b . sin C = c . sin B Or, expressed in a proportion... | |
| Robert Gibson - 1832 - 290 páginas
...when the given angle is acute, and opposite the less of the given sides,the answer is ambiguous, as the sine of an angle is equal to the sine of its supplement, consequently the required angle opposite that other given side may be obtuse or acute, unless if is... | |
| Henry Pearson - 1833 - 164 páginas
...angle is equal to the sine of its complement. C 7. Sin (TT - 9) = sin 9, cos (TT - 9) = - cos Q. Or the sine of an angle is equal to the sine of its supplement, and the cosine of an angle is equal to the cosine of its supplement, with its algebraical sign changed. B 8. PROPOSITION.... | |
| John Charles Snowball - 1837 - 322 páginas
...determine B from (ii), С and с are known from (i) and (iii), and the triangle is determined. Now the sine of an angle is equal to the sine of its supplement, and therefore there are two angles which satisfy (ii), the one greater and the other less than 90°. (1).... | |
| Nathan Scholfield - 1845 - 506 páginas
...Therefore, -=^that is, sin. «=sin. (180° — «) an important proposition which enunciated in words, is, the sine of an angle is equal to the sine of its supplement. Again, cs=cs; CA~CA cos. t= — cos. (180° — d), 42 If, as in the annexed figure, we draw CP', making... | |
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