PROOF. Add the total remainder, or answer, to the subtrahend, by the rule for Compound Addition; and, if the work be right, the amount will be equal to the minuend. EXAMPLES. Money. 1. From 5727. 15 s. 11 d. take 284 7. 8 s. 6d. L. S. d. Remainder, 288.. 7.. 5 572.. 15.. 11 Here I first subtract the 6 pence from the 11 pence, as in Simple Subtraction, and the remainder is 5 pence, which I set down underneath. I subtract, in like manner, the 8 shillings from the 15 shillings, and the 284 pounds from the 572 pounds, and set down the remainders, 7 and 288. So the whole remainder, or answer, is found to be 2887. 7s. 5d. Then, to prove the work, I add the whole remainder to the subtrahend, (by Compound Addition,) and the sum being the same as the minuend, I conclude the work is right. (2) S. d. q. From 18.. 5 .. 2 take 4..7..3 Rem. 13.. 9.. 3 Here, as I cannot subtract 3 farthings from 2 farthings, I borrow 4 farthings, (which are equal to 1 penny,) and add them to the 2 farthings, and the sum is 6 farthings, from which I subtract the 3 farthings, and set down the remainder. Then I carry 1 penny, (as an equivalent to the 4 farthings borrowed,) and add it to the 7 pence, and the sum is 8 pence. Then, as I cannot subtract 8 pence from 5 pence, I add 12 pence (which make 1 shilling) to the 5 pence, and from the amount I subtract the 8 pence, and set down the remainder. Then I add 1 to the 4 shillings, and subtract the sum from the 18 shillings, and set down the remainder, and the work is done. Note.-In Compound Subtraction, when it is necessary to borrow, instead of adding the number borrowed to the upper number, and then subtracting the lower number from the amount, as directed in the foregoing Rule, you may, if you choose, subtract the lower number from the number borrowed, and add the remainder to the upper number, and set down the amount below; then carry 1 to the next superior denomination in the subtrahend; and so, proceed. 5. From 187. 12s. 4d. take 157. 0 s. 2d. Ans. 31. 12 s. 2d. 6. Find the difference between 2177. 6 s. and 1787. 18 s. Ans. 38 l. 7 s. 6d. 3q. 5 d. 1 q. 1. Bought a piece of cloth for 2l. 19s.; and sold the same for 37. 18s. 6d.: what did I gain by the bargain? Ans. 19s. 6d. 2. The value of the domestic and foreign produce exported from the United-States to foreign countries, in the year 1800, was 159686507. 10 s. sterling. The value of the exports from the city of London, in the same year, was 254289227. 16s. 7d. How much did the value of the exports from London exceed that of the exports from the United-States? Ans. 91602721. Gs. 7d. 3. A Silversmith had 14 lb. 9 oz. 10 pwt. of silver; he melts 7lb. 15 pwt. 10 gr.; how much has he left? Ans 7 lb. 8 oz. 14 pwt. 14 gr. 4. The highest mountain in the known world is Dewalageri, the loftiest peak of the Himmaleh mountains, in Asia; and the next highest is Chimborazo, in South-America. The summit of Dewalageri is about 5 miles, 1 furlong, 37 rods, and that of Chimborazo 4 miles and 18 rods, above the level of the sea. How much does the height of Dewalageri exceed that of Chimborazo ? Ans. 1 m. 1 fur. 19 rd. 5. Bought several casks of cider, containing 152 gallons, 1 quart; and disposed of one which contained 41 gallons, 2 quarts, 1 pint: How much remained in the other casks? Ans. 110 gal. 2 qt. 1 pt. 6. Napoleon Bonaparte was born in the town of Ajaccio, on the island of Corsica, the 15th of 8th Month (August) 1769; and he died on the island of St. Helena, the 5th of 5th Month (May) 1821. How old was he when he died? yr. mo. da. 1821..5.. 5 1769..8.. 15 Ans. subsequent date. prior date. 51..8.. 20 difference. Note. To find the interval or space of time between any two given dates; subtract the years, months, and days, of the prior date, from those of the subsequent date, and the difference will be the time sought. When the number of days in the subtrahend exceeds the number in the minuend, subtract the former number from the number of days that the month next before that mentioned in the minuend contains, if this subtraction can be made; add the remainder to the number of days in the minuend, and set down the sum, for the number of days in the answer: but if this subtraction cannot be made, then the number of days in the minuend will be the number to set down in the answer. Always when the number of days in the subtrahend is greater than the number in the minuend, add 1 to the number of months in the subtrahend. In other respects proceed according to the rule for Compound Subtraction. Thus, In the foregoing example, the number of days in the sub |