Ex. 2. A mixture, whose specific gravity is. 8784, is made of tin and copper, and weighs 112 lb.; the fpecific gravity of tin is. 7320, and of copper 9000; how much of each ingredient? 100 lb. copper. 12 1. tin. Anf. { Ex. 3. A goldsmith mixes 18 ounces gold with alloy, and forms a mass of 24 ounces, whose specific gravity is 18000; the specific gravity of gold is 19637 i required the specific gravity of the alloy Ang. PROBLEM IV. To find the weight af a body from its magnitudea RULE. As i cubic foot EXAMPLE I. Required the weight of a block of marble 6 feet long, 5 broad, and 6 Inches thick. Ex. 2. Required the weight of a log of oak 24 feet long, 11 broad, and 1 foot thick. Ans. 18 cwt. 2 qrs. 9 lb. 4 oz. Ex. 3. How many deals fir will a fhip of 400 ton burden carry, each being 16 feet long, 9 inches broad, and 6 inches thick ? Anf. 4344 Ex. 4. A ship of 300 tons burden carries 96 Nabs marble, each 10 feet long and 6 feet broad; it is required to find the thickness. Anf. 3.296 inches. PROBLEM PROBLEM V. To find the magnitude of bodies from their weights, RULE. Divide the weight of the body in averdupois ounces by the tabular specific gravities, for the number of cubic feet. Or say, As the specific gravity of the body EXAMPLE I. How many cubic feet are in a ton weight of fir 550 : 35840 :: 1:6535 Ex. 2. How many cubic feet are in a ton-weight of brass ? Ans. 4.48. Ex. 3. How many cubic feet in a block common stone, whose weight is 8 ton? Anf. 1137 feet. A TABLE of Specific Gravities of several Solids and. Fluids. Very fine gold 19637 18888 17793 17140 14019 21325 11087 10535 8843 8000 7850 7645 7425 7321 7065 6800 5280 3775 3400 3150 2707 2700 2658 2620 2568 2520 2542 2460 2000 Brick Nitre Alabaster Dry ivory Brimstone Solid gunpowder Allum Sand Pit-coal Pitch Ebony Human blood Amber Cows milk Sea-water Goats milk Pump-water Spring-water Distilled water Proof of spirits Dry oak Gunpowder fhaken Pure fpirits Ash Crabtree Maple Elm Fir Cork Air 2000 1900 1875 1825 1800 1745 1714 1520 1 240 1150 1117 1054 1030 1030 1030 1003 1000 999. 993 931 925 922 866 800 765 755 600 550 240 BALLS BALLS AND SHELLS. PROBLEM I. To find the weight of a pell, the external and internal diameters being given. RULE. MULTIPLY the difference of the cubes of the diameters itt inches by .14, and the product gives the answer in pounds nearly. Required the weight of an iron shell, whose external and internal diameters are 95 and 7 inches. 598.192 |