A Complete Treatise on Practical Mathematics: Including the Nature and Use of Mathematical Instruments: Logarithmic Tables, Trigonometry, Mensuration of Heights and Distances,--of Surfaces & Solids, Land Surveying, Gunnery, Gauging, Artificer's Measuring, Miscellaneous Exercises. With an Appendix on Algebra ... Principally Designed for the Use of Schools and AcademiesBell and Bradfute, 1792 - 431 páginas |
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Página xi
... Spindle , - - 199 To find the Solidity of a circular Spindle , - 201 To find the Solidity of the middle Zone of a circular Spin- dle , - - 203 To find the Area and Solidity of the five regular Bodies , 206 To find the Surface and ...
... Spindle , - - 199 To find the Solidity of a circular Spindle , - 201 To find the Solidity of the middle Zone of a circular Spin- dle , - - 203 To find the Area and Solidity of the five regular Bodies , 206 To find the Surface and ...
Página 199
... spindle . RULE . Multiply the length of the spindle by the radius of the re- volving arch ; again multiply the distance between the centre of the revolving arch and the centre of the spindle by the length of of the revolving arch ...
... spindle . RULE . Multiply the length of the spindle by the radius of the re- volving arch ; again multiply the distance between the centre of the revolving arch and the centre of the spindle by the length of of the revolving arch ...
Página 200
... spindle , whose length is 40 and thickness 30 inches . AD2 BD AD2 + BD2 = AB the chord of the arch ABC ; that is , 400 + 225 = 25 = DH and DH + BD = FB rad . also FB - BD = DF cent . dift . 400 2 - = 26.6 and 26.6 + 16 = 20.83 rad ...
... spindle , whose length is 40 and thickness 30 inches . AD2 BD AD2 + BD2 = AB the chord of the arch ABC ; that is , 400 + 225 = 25 = DH and DH + BD = FB rad . also FB - BD = DF cent . dift . 400 2 - = 26.6 and 26.6 + 16 = 20.83 rad ...
Página 201
... spindle , whose length is 80 and thickness 16 inches ? Ans . 2747-3166336 . Ex . 3. Required the area of a circular spindle , whose length is 12 , and thicknefs y inches . Ans . 294.3621 fq . inches . PROBLEM XVII . To find the ...
... spindle , whose length is 80 and thickness 16 inches ? Ans . 2747-3166336 . Ex . 3. Required the area of a circular spindle , whose length is 12 , and thicknefs y inches . Ans . 294.3621 fq . inches . PROBLEM XVII . To find the ...
Página 202
... sector AFCB . 8.75 × 30 = 262.5 the area of the triangle ACF . 987.5 the area of the rev . segm . ACB . 4.375 the half the central dift . DF . 49375 60125 29625 29500 4320.3125 бо 30 half the spindle . 30 -- 900 30 3 202 MENSURATION.
... sector AFCB . 8.75 × 30 = 262.5 the area of the triangle ACF . 987.5 the area of the rev . segm . ACB . 4.375 the half the central dift . DF . 49375 60125 29625 29500 4320.3125 бо 30 half the spindle . 30 -- 900 30 3 202 MENSURATION.
Términos y frases comunes
abfciffa abſciſſa acres alſo altitude amplitude bafe becauſe breadth centre chord of half circle circumference Co-tan column conjugate conſequently correſponding cubic deſcribe diſt diſtance divided elliptic equal EXAMPLE fame feet fide fimilar find the area find the folidity firſt fruſtum fubtract furface given half the arch horizontal houſe hyperbola inches inſtrument leſs logarithm malt buſhels meaſure multiply the ſum object obſerved off-fets oppoſite ordinate parabola perpendicular plane Plate PROBLEM quotient radius 90 rectangle Required the area Required the folidity rhombus right angles RULE ſame ſay Secant Co-fec ſecond ſegment ſhadow ſhall ſolidity ſpaces ſphere ſpheroid ſpindle ſquare root ſquare yards ſtaff ſtation ſteeple ſtraight line ſuch ſum ſuperficies tangent theodolite theſe tranſverſe trapezium triangle uſed verſed ſine whoſe baſe whoſe diameter whoſe height whoſe length whoſe ſide wine gallons Το
Pasajes populares
Página 27 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, etc.
Página 103 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Página 3 - A diameter of a circle is a straight line drawn through the centre, and terminated both ways by the circumference.
Página 220 - E, is equal to twice as many right angles as the figure has sides, less four right angles.
Página 1 - ... common to the two triangles AFE, BFE, there are two sides in the one equal to two sides in the other, each to each ; and the base EA is equal to the base EB ; (i.
Página 38 - BG; that is, the fum of the fides is to their difference, as the tangent of half the fum of the angles at the bafe to the tangent of half their difference.
Página 352 - Subtract the square number from the left hand period, and to the remainder bring down the next period for a dividend. III. Double the root already found for a divisor ; seek how many times the divisor is contained...
Página 38 - AB the greater side for a distance, let a circle be described, meeting AC, produced in E, F, and BC in D; join DA, EB, FB; and draw FG parallel to BC, meeting EB in G. The angle EAB (32.
Página 38 - ACB (32. 1.) is equal to the angles CAD and ADC, or ABC together ; therefore FAD is the difference of the angles at the...
Página 375 - TO divide a given ftraight line into two parts, fo that the rectangle contained by the whale, and one of the parts, fhall be equal to the fquare of the other part. Let AB be the given ftraight line; it is required to divide it into two parts, fo that the rectangle contained by the whole, and one of the parts, fhall be equal to the fquare of the other part. Upon AB...