 | Robert Simson - 1775 - 534 páginas
...center (20.3.); therefore EFB is half the fum of the angles at the bafe; but the angle ACB. (32.i.) is equal to the angles CAD and ADC, or ABC together; therefore FAD is the dillerence of the angles at the bafe, and FED at the circumference, or BFG, on account of the parallels... | |
 | Robert Simson - 1781 - 534 páginas
...center (20. 3.); therefore EFB is half the fum of the angles at the bafe; but the angle ACB (32. i.) is equal to the angles CAD and ADC, or ABC together...FAD is the difference of the angles at the bafe, and FED at the circumference, or BFG, on account of the parallels FG, BD, is the half of that difference... | |
 | Euclid - 1781 - 552 páginas
...fum of the angles at the bale ; but the angle ACB (32. r.) is equal to the angles CAD and ADC, or'ABC together; therefore FAD is the difference of the angles at the bafe, and FBD at the circumference, or 15FG, on account of the parallels FG, BD, is the half of that difference ;... | |
 | Robert Simson - 1804 - 530 páginas
...center (20. 3.); therefore EFB is half the fum of the angles at the bafe; but the angle ACB (32. i.) is equal to the angles CAD and ADC, or ABC together...the difference of the angles at the bafe, and FBD at the circumference, or BFG, on account of the parallels FG, BD, is the half of that difference ;... | |
 | Robert Simson - 1806 - 546 páginas
...centre (50. 3.); therefore EFB is half the sum of the angles at the base; but the angle ACB (32. 1.) is equal to the angles CAD and ADC, or ABC together...therefore FAD is the difference of the angles at the base, and FBD at the circumference, or BFG, on account of the parallels FG, BD, is the half of that... | |
 | Euclides - 1816 - 588 páginas
...centre (20. 3.); therefore EFB is half the sum of the angles at the base; but the angle ACB (32. 1.) is equal to the angles CAD, and ADC or ABC, together:...therefore FAD is the difference of the angles at the base, and FED at the circumference; or BFG, on account of the parallels FG, BD, is the half of that... | |
 | Euclid, Robert Simson - 1821 - 514 páginas
...centre (20. 3.); therefore EFB is half the sum of the angles at the base; but the angle ACB (32. 1.) is equal to the angles CAD and ADC, or ABC together: therefore FAD is the difference of th angles at the base, and FBD at the circumference, or BFG, on account of the parallels FG, BD, is... | |
 | Robert Simson - 1827 - 546 páginas
...centre (20. 3.); therefore EFB is half the sum of the angles at the base ; but the angle ACB (32. 1 .) is equal to the angles CAD and ADC or ABC together...therefore FAD is the difference of the angles at the base, and FBD at the circumference, or BFG, en account of the parallels FG, BD, is the half of that... | |
 | Euclides - 1834 - 518 páginas
...equal to the half of EAB at the centre * ; therefore EFB is half the sum of the angles at the base ; but the angle ACB * is equal to the angles CAD and...therefore FAD is the difference of the angles at the base, and FBD at the circumference, or BFG, on account of the parallels FG, BD, is the half of that... | |
 | Euclid - 1835 - 540 páginas
...centre, (20. 3.) ; therefore EFB is half the sum of the angles at the base ; but the angle ACB (32. 1.) is equal to the angles CAD and ADC, or ABC together...therefore FAD is the difference of the angles at the base, and FBD at the circumference, or BFG, on account of the parallels FG, BD, is the half of that... | |
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ACB (32. 1.) is equal to the angles CAD and ADC, or ABC together ; therefore FAD is the difference of the angles at the... 