| 1801 - 426 páginas
...street. • t Ans. 76- 1 2333 35 feet. PROBLEM IV. 7o f:nd tlie area of a trapezoid. • RULE.* Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. • EXAMPLES. * DEMONSTRATION. or (because B»=DE) =-, .-. A... | |
| Thomas Keith - 1817
...trapezium 85342'2885 yards, or 17•6327 acres; or 17 acres. <• 2 roods 21 perches. PROBLEM VIII. • **To find the Area of a Trapezoid. RULE *. Multiply...sides by the perpendicular distance between them,** and the product will be the area. Example 1. Let AB c D JE. be a trapezoid, the side '-. A )•. —... | |
| Anthony Nesbit, W. Little - 1822
...Ant. 97.3383 bushels. PROBLEM VII. To Jind the area of a trapezoid. RULE. • By the Pen. Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area in square inches. Divide this area by 2 82, 231, and 2150.42,... | |
| John Nicholson - 1825 - 795 páginas
...square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12,... | |
| Zadock Thompson - 1826 - 164 páginas
...rods ; what is the area ? Ans. 54.299 rods. I Problem III. Tojind the area of a trapezoid. :BuLE.— **Multiply half the sum of the two parallel sides by the perpendicular distance between them,** and the product will be the area. Examples. 1. One of the two parallel sides of a trapezoid is 7.5... | |
| James Hale - 1829 - 115 páginas
...(See Def. 32, 33, and 35, Part. 1, Sec. 1.) PROBLEM VI. To find the Area of a Trapezoid. (See Def.M.) **Multiply half the sum of the two Parallel Sides by the Perpendicular** Height, the Product is the Area. PROBLEM VII. To find the Area of a Trapezium. (See Def. 36 and S7.)... | |
| John Nicholson (Civil engineer) - 1830 - 182 páginas
...square 63 I 189 of AB has been subtracted. 3 I 189 Prob. 4. To find the Area of aTrapezoid. Multiply **the sum of the two parallel sides by the perpendicular distance between them,** and half the product will be the area. Ex. In a trapezoid, the parallel sides are AB 7, and CD 12,... | |
| Ira Wanzer - 1831 - 396 páginas
...many acres are contained in a triangle whose sides are 30, 40, and 50 rods? Ans. 3f A. PROBLEM V, — **To find the area of a Trapezoid. RULE. — Multiply...sides by the perpendicular distance between them,** and the pr«' duct will be the area. Ex. How many square feet are contained in a board which is 12... | |
| Zadock Thompson - 1832 - 168 páginas
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find the area of a trapezoid. (65) **RULE. — Multiply half the sum of the two parallel...sides by the perpendicular distance between them,** and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and... | |
| Zadock Thompson - 1832 - 168 páginas
...16, 11 and 10 rods ; what is the area ? Ans. 54.299 rods. 307. To find (he. area of a trapezoid. (65) **RULE. — Multiply half the sum of the two parallel...sides by the perpendicular distance between them,** and the product will be the area. 1. One of the two parallel sides of a trapezoid is 7.5 chains, and... | |
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