 | Alexander Ingram - 1830 - 458 páginas
...both ends ind loaded in the centre. RULE. Multiply the tabular value of S by 4 times the breadth and square of the depth in inches, and divide the product by the length in inches for the weight. NOTE 1 . When the beam \sjixed at each end, and loaded in the middle, the result... | |
 | William Turnbull - 1832 - 234 páginas
...times the breadth in inches by the sum of the segments of the length of bearing in feet, drawn into the square of the depth in inches, and divide the product by the rectangle of the segments, for the load to be supported in pounds. Example 5. In the equation there... | |
 | William Templeton (engineer.) - 1833 - 224 páginas
...— Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in libs, avoirdupois nearly. H2 Kama of Dailies. *;. Bar. 1 third.... | |
 | Charles Haynes Haswell - 1844 - 298 páginas
...oath. Ends, and Loaded in the Middle. RULE. — Multiply the Value in the preceding table by six times the breadth, and the square of the depth, in inches, and divide by the length in feet. NOTE.— When the weight is laid uniformly along its length, the result must... | |
 | Oliver Byrne - 1851 - 310 páginas
...— Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in Ibs. avoirdupois. What weight will break a beam of oak 4 inches... | |
 | Charles Haynes Haswell - 1851 - 346 páginas
...both Ends, and Loaded in the Middle. RULE. — Multiply the Value in the preceding table by six times the breadth, and the square of the depth, in inches, and divide by the length in feet. NOTE.— When the weight is laid uniformly along its length, the result must... | |
 | William Somerville Orr - 1856 - 556 páginas
...carricd by a beam 1 inch broad, 1 inch deep, and 1 foot long, by the breadth in inches, and twice by the depth in inches, and divide the product by the length in feet. Example. — A beam 1 inch square and 1 foot long, carrics 5 cwt. at its end : required the load carried... | |
 | W.E. WORTHEN - 1857 - 600 páginas
...centre : Rule — Multiply the constant S, for the material from the above table, by the breadth and square of the depth in inches, and divide the product by the length in feet. Example. — What is the ultimate strength of a beam of white pine, 20 feet long, 8 inches wide, and... | |
 | William Ezra Worthen - 1857 - 650 páginas
...centre : Rule — Multiply the constant S, for the material from the above table, by the breadth and square of the depth in inches, and divide the product by the length in feet. Example. — What is the ultimate strength of a beam of white pine, 20 feet long, 8 inches wide, and... | |
 | Oliver Byrne - 1863 - 600 páginas
...— Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in Ibs. avoirdupois. What weight will break a beam of oak 4 inches... | |
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Multiply the strength of an inch square bar, 1 foot long, (as in the table,) by the breadth, and square of the depth in inches, and divide the product by the length in feet ; the quotient will be the weight in Ibs. 
