| 1801 - 446 páginas
...diminished, is called the ratio. PROBLEM I. Given the first termt the last term, and the ratio, to find tht sum of the series. RULE.* Multiply the last term by...ratio, and from the product subtract the first term, and the remainder, divided by the ratio less I, will give the sum of the series. EXAMPLES. * DEMONSTRATION.... | |
| Samuel Webber - 1808 - 466 páginas
...calfed the r'atio. PR0BLEM I. Giyen thejirst term, the last term, and the ratio, to find the sum of thc series. RULE.* Multiply the last term by the ratio, and from the product subtract the first term, and the remainder, divided by the ratio less 1, will give the sum of the series. • DEM0NSTRATI0N.... | |
| Samuel Webber - 1812 - 260 páginas
...increased or diminished, is called the ratio. PROBLEM 1. Given thefirst term, the last term, and the ratio, to find the sum of the series. RULE.* Multiply the...ratio, and from the product subtract the first term, and the remainder, divided by the ratio less 1, will give the sum of the series. * DEMONSTRATION. Take... | |
| Jeremiah Joyce - 1812 - 274 páginas
...determined. I. Given the first term a, the last term z, and the common ratio r, to find the sum s. RULE. Multiply the last term by the ratio, and from the product subtract the first term, and the remainder divided by the ratio, less one, will give the sum of the series ; or — r — 1... | |
| Nathan Daboll - 1818 - 246 páginas
...8, 1 6, &c. increase by the multiplier 2 ; and 27, $, 3, 1, decrease by the divisor 3. PROBLEM I. >i The first term, the last term (or the extremes) and...the sum of the series. RULE. Multiply the last term fay the ratio, and from the product subtract the first term ; then divide the remainder by the- ratio,... | |
| 1818 - 264 páginas
...is called the RATIO. PROBLEM I. Given the first term, the last term, (or extremes') and the ra* t|O, to find the sum of the series, RULE. Multiply the...ratio, and from the product subtract the first term, and the rem ainder, divided by the ratio less I, wjif'give the sum of all the terms of the series.... | |
| Phinehas Merrill - 1819 - 116 páginas
...answer. CASE H. •Given the first term, the last term, and the ratio, to find the aggregate or total sum of the series. RULE. — Multiply the last term...ratio, and from the product subtract the first term, and the remainder, divided by the ratio less one, will give the sum of the whole series. EXAMPLES.... | |
| Nicolas Pike - 1822 - 536 páginas
...terms ? Ana. £Jff. Ill 18. What is the sura of j-^t, f^.^p- &c. to infinity ? Ans. 16f. PROBLEM IH. The .first term, the last term (or the extremes) and the ratio given, ft> Jlnd the snm of the series.^. RULE I. Divide the difference of the extremes by the ratio legs by... | |
| Nathan Daboll - 1823 - 262 páginas
...8, 16, &.c. increase by the multiplier 2: and S7, 9, 3, 1, decrease by the divisor 3. PROBLEM I. . ' The first term, the last term (or the extremes) and the ratio given, to fmd the-sum of the series. RULE. Multiply the last term by t!ie ratio, and from the product subtract... | |
| Zadock Thompson - 1826 - 176 páginas
...is called the ratio. Problem I. The Jlnt term, the latt term, and the ratio given to find the turn of the series. RULE.* — Multiply the last term by...ratio, and from the product subtract the first term, and the remainder divided by the ratio, less 1, will give the sum of the series. Examples. 1 . The... | |
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