26. б.х? - 17ax + 12а? - 30ах? + 85a3х – боа? 3* - 4a)247 – 98ax: + 133a** - 6009 (8.12 – 222x + 1522 боа" (8424х3 - ? 28. x2 + 4ax + 3a?).*+ 30x' + a*x + 3a*(*2 – ax + a? за** - ах – 3g?х? + a*х а?х? + 4a3x + за If as 2. x2 + (x2 - 42x+89)}, when x = 2, =4+(4 - 84+89)* = 4 + Vg24+3=7 or 1. at sa2 +62 a3 - 26(a? - 62) - b, and b= -3, -b+ 202 +22 -bt/262 - 13 - 26(62 - 62) -63 6- 262 63 =(3+ 118) - 27 = (1 + 12). 3. (a) By x – 50. у 4. (2 + 3x + 4x4)2-(2 - 3x + 4.x2) = (4 + 12x + 25x2 + 24.x3 + 16x4) - (4 – 12x + 25x2 – 24x3 + 16x4) = 4 + 12x+ 25x2 + 24x3 + 16x4 – 4 + 12x – 25x2 + 24.78 – 16x4 = 24x + 48.x3 = 24*(1 + 2x2). a 5. The parts of a compound expression connected by the signs + and - are called terms-e.x, in a2 +62 -, a, b, and 6’ ( are terms. Coefficient=co-factor. ac is produced by a xc, in which each of the factors a and c is a coefficient of the other. An index is a number placed over a quantity to show how many times it occurs as a factor in a power; thus, in 33, 3 is the index which shows that x occurs as a factor three times, as X X X X X. A negative quantity is a quantity with the minus sign prefixed, as - a. In the quantity abc, a, b, c are factors, because they make by multiplication the quantity abc. 12x2 + xy - 63.72 = (3x + 7y) (4x - wy). 6. See No. 5. = (a + b) 7. (12 + xy + y2)2 = (x2 - xy + y2)2 + 4xy(x2 + y2), + , x4 = x+ + 2x3y + 3x+y2 + 2xy + y^. If x = 5, and y= -5, show that (x2 + xy + y2)2 = (^2 - xy + y2)2 + 4xy(x2 + 3,2). Substituting the above values, or 252= 752 - 5000, = 625. 8. Show that x(x + 1) (x + 2) (x + 3) + 1 = (x2 + 3x + 1)2. Multiplying out, and squaring opposite side, we have *4 + 6x3 + 11x2 + 6x +1 = x4 + 6x3 + 11x2 + 6x + 1. 9. Let a? – b2 be divided by a +b, where a+b is the sum of the two quantities a and b, and a? - 62 is the difference of their squares. Here the quotient is a - b, which is the difference of the two quantities a and b. (aox? + b2y2) - (a2b2 + x2y2)= x(a? - y2) – bo(a? - y2) ax + by + ab + xy = x(a +y)+ b(a + y). 3b *(a + y) + B(a +y))x?(a– y2) – bo(a? - y2)(x(a – y) – b(a - y) Ix®(a2 - y2) + bx(a2 - y2) = (x -b) (a - y) 3– 10. a +a+a+etc. 6 times = ba. then (3 + 4)2 – 1 = 3 X 4 X 4 = 48, 72-I = 48 49 - 1 = 48. = 11. X-(a - b)x3 + (a - b)028 – b4; find value when a= = , and b=0. As b=0, all the terms which contain it vanish, and the expression becomes #4 - ax: or x®(x - a), which, as a = - * .. **= 1, 2X* = 5 . 1 SIMPLIFICATION. 1. ala – 1) (a – 2) (a - 3) = 24 - 6a3 + 1122 - 6a. If a = 4, the expression becomes 4.3.2= 24. 2. 4.x -[(4x - 4y) (4x + 4y) -- {4x +(4x + 4y) (4.x – 4y)} + 4y] = 4x - [16x2 - 16y2 - 4x + 16x2 – 16y2} + 4y] -8. I 3. x(x + y) +*- {x(x - y) + (x + y) (x - y) - 66} ***+ xy + x - x2 - xy + x2 - y2 - 66} 4. See Mansford, page 13. 3(x2 + y2) - {x2 + 2xy + y2 - (2 + y - 42 - y2))} = 3x2 + 3y2 - {x2 + 2xy + y2 – 2- y + x2 + y2} 3.x2 + 3y2 - ** - 2xy = y* + 2+ y - x - y Collecting = x2 - 2xy + y2 + y + 2. 5. (a + b + c)2 - a(b+c-a) - bla+c-) - ca+b-) - ac - bc +62 |