Euclid's Elements of geometry, the first three books (the fourth, fifth, and sixth books) tr. from the Lat. To which is added, A compendium of algebra (A compendium of trigonometry).1846 |
Dentro del libro
Resultados 1-5 de 28
Página 5
... equiangular . 32. Rectilineal figures which have more than four sides , are called polygons . POSTULATES . 1. Let it be granted that a right line can be drawn from any point to another . 2. That a terminated right line can be produced ...
... equiangular . 32. Rectilineal figures which have more than four sides , are called polygons . POSTULATES . 1. Let it be granted that a right line can be drawn from any point to another . 2. That a terminated right line can be produced ...
Página 10
... equiangular ; for whatsoever side is assumed for the base , the adjacent angles will be equal , because the equal sides are opposite . PROPOSITION VI . THEOREM . If two angles ( B and C ) of a triangle ( BAC ) be equal , the sides ...
... equiangular ; for whatsoever side is assumed for the base , the adjacent angles will be equal , because the equal sides are opposite . PROPOSITION VI . THEOREM . If two angles ( B and C ) of a triangle ( BAC ) be equal , the sides ...
Página 148
... equiangular to a given triangle ( EDF ) . Draw the right line GH , touching the given circle in any point A ; and at the point . A , with the line AH , con- struct the angle HAC , equal to E ; and at the same point , with the right line ...
... equiangular to a given triangle ( EDF ) . Draw the right line GH , touching the given circle in any point A ; and at the point . A , with the line AH , con- struct the angle HAC , equal to E ; and at the same point , with the right line ...
Página 149
... equiangular to the given triangle . PROPOSITION IV . PROBLEM . To inscribe a circle in a given triangle ( BAC ) . A Bisect any two angles B and C , by the right lines BD and CD , and from the point in which these right lines meet , draw ...
... equiangular to the given triangle . PROPOSITION IV . PROBLEM . To inscribe a circle in a given triangle ( BAC ) . A Bisect any two angles B and C , by the right lines BD and CD , and from the point in which these right lines meet , draw ...
Página 155
... which the given line BD may be a side ; and produce BC , make the angle BDA equal to the angle B , BA and DA meet , and that required shall be done . PROPOSITION XI . PROBLEM . To inscribe an equiangular and FOURTH BOOK . 155 37.
... which the given line BD may be a side ; and produce BC , make the angle BDA equal to the angle B , BA and DA meet , and that required shall be done . PROPOSITION XI . PROBLEM . To inscribe an equiangular and FOURTH BOOK . 155 37.
Términos y frases comunes
absurd AC and CB AC by Prop AC is equal angle ABC angle equal angles by Prop arch bisected centre circumference co-efficient Const construct contained oftener diameter divided divisor double equal angles equal by Constr equal by Hypoth equal by Prop equal right lines equal to AC equal to twice equi-multiples equi-submultiples equiangular equilateral external angle fore fraction given angle given circle given line given right line given triangle greater half a right inscribed less multiplied opposite parallel parallelogram perpendicular PROPOSITION quantities quotient ratio rectangle under AC remaining angles remaining side right angle right line AB right line AC SCHOL segment semicircle side AC similar similarly demonstrated squares of AC submultiple subtract THEOREM tiple touches the circle triangle BAC twice the rectangle twice the square whole
Pasajes populares
Página 20 - If two triangles have two sides of the one equal to two sides of the...
Página 30 - DE : but equal triangles on the same base and on the same side of it, are between the same parallels ; (i.
Página 209 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Página 218 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Página 114 - To reduce fractions of different denominators to equivalent fractions having a common denominator. RULE.! Multiply each numerator into all the denominators except its own for a new numerator, and all the denominators together for a common denominator.
Página 90 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Página 129 - In any proportion, the product of the means is equal to the product of the extremes.
Página 163 - Magnitudes are said to be in the same ratio, the first to the second and the third to the fourth, when, if any equimultiples whatever be taken of the first and third, and any equimultiples whatever of the second and fourth, the former equimultiples alike exceed, are alike equal to, or alike fall short of, the latter equimultiples respectively taken in corresponding order.
Página 215 - ... are to one another in the duplicate ratio of their homologous sides.
Página 160 - PROPOSITION XV. PROBLEM. To inscribe an equilateral and equiangular hexagon in a given circle. Let ABCDEF be the given circle.