Elements of Geometry: With Practical Applications ...H.H. Howley and Company, 1847 - 308 páginas |
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Página 17
... ( Prop . II ) : consequently the angle DGB is equal to the angle DGF ; but DGF is equal to the opposite angle AGC ( Prop . II ) ; hence the angle BGD is equal to AGC . ( 22. ) Suppose AC and BD to represent two trees standing on the ...
... ( Prop . II ) : consequently the angle DGB is equal to the angle DGF ; but DGF is equal to the opposite angle AGC ( Prop . II ) ; hence the angle BGD is equal to AGC . ( 22. ) Suppose AC and BD to represent two trees standing on the ...
Página 21
... ( Prop . II ) ; therefore these two triangles are equal in all respects ( Prop . II ) , and we have the angle ACF equal to the angle GBF ; consequently the exterior angle CBD , being greater than GBF , is greater than the interior angle ...
... ( Prop . II ) ; therefore these two triangles are equal in all respects ( Prop . II ) , and we have the angle ACF equal to the angle GBF ; consequently the exterior angle CBD , being greater than GBF , is greater than the interior angle ...
Página 23
... ( Prop . v ) . In like manner , in the triangle BCD , since BC is equal to BD , we have the angle BCD equal to the angle BDC . Hence the angle ACB , which is the sum of ACD and BCD , is equal to the angle ADB , which is the sum of ADC and ...
... ( Prop . v ) . In like manner , in the triangle BCD , since BC is equal to BD , we have the angle BCD equal to the angle BDC . Hence the angle ACB , which is the sum of ACD and BCD , is equal to the angle ADB , which is the sum of ADC and ...
Página 25
... ( Prop . II ) , and consequently DC is equal to FA . = By comparing the triangles ACF and GCB , it may be shown that they also are equal , and consequently FA is equal to GB . It might , moreover , be shown that these lines all intersect ...
... ( Prop . II ) , and consequently DC is equal to FA . = By comparing the triangles ACF and GCB , it may be shown that they also are equal , and consequently FA is equal to GB . It might , moreover , be shown that these lines all intersect ...
Página 26
... Prop . IX , and the equality of the angles will follow from Prop . VIII . For , drawing lines from B to C , and from F to G ( Post . I ) , we have the three sides of the triangle ABC equal to the three sides of the triangle DFG ...
... Prop . IX , and the equality of the angles will follow from Prop . VIII . For , drawing lines from B to C , and from F to G ( Post . I ) , we have the three sides of the triangle ABC equal to the three sides of the triangle DFG ...
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Términos y frases comunes
a+b+c AC² altitude angle ACD angle BAC bisect centre chord circ circular sector circumference cone consequently convex surface cylinder diagonal diameter distance draw equal and parallel equiangular equilateral triangle equivalent exterior angle figure formed four right angles given line greater half the arc hypothenuse inscribed circle intersection isosceles join less Let ABC lines drawn magnitude measured by half meet multiplied number of sides opposite angles parallel planes parallelogram parallelopipedon pendicular perimeter perpendicular plane MN point G prism PROBLEM produced Prop PROPOSITION pyramid radii radius rectangle regular polygon respectively equal right angles right-angled triangle Sabc Schol Scholium semicircle semicircumference side AC similar similar triangles solid angle solid described sphere spherical triangle square straight line suppose tangent THEOREM three sides triangle ABC triangular prism vertex VIII
Pasajes populares
Página 37 - The sum of all the angles of a polygon is equal to twice as many right angles as the polygon has sides, less two.
Página 180 - THEOREM. If one of two parallel lines is perpendicular to a plane, the other will also be perpendicular to this plane. Let AP & ED be parallel lines, of which AP is perpendicular to the plane MN ; then will ED be also perpendicular to this plane.
Página 139 - PROBLEM. To inscribe a circle in a given triangle. Let ABC be the given triangle : it is required to inscribe a circle in the triangle ABC.
Página 224 - The radius of a sphere is a straight line, drawn from the centre to any point of the...
Página 43 - In a right-angled triangle, the side opposite the right angle is" called the Hypothenuse ; and the other two sides are cal4ed the Legs, and sometimes the Base and Perpendicular.
Página 184 - THEOREM. If two angles, not situated in the same plane, have their sides parallel and lying in the same direction, they will be equal, and the planes in which they are situated will be parallel.
Página 10 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another.
Página 226 - We conclude then, that the solidity of a cylinder is equal to the product of its base by its altitude.
Página 22 - If two sides and the included angle of the one are respectively equal to two sides and the included angle of the other...
Página 12 - If equals be added to unequals, the wholes are unequal. V. If equals be taken from unequals, the remainders are unequal. VI. Things which are double of the same, are equal to one another.