EXAMPLES. 1. What will 354 yards cost, at d. per yard? S. d. d.354 6 value of 354 yards, at 1s. per yard. Ans. £0 7 4 value of 354 yard, at d. per yard. 74 Ans. as before. 2. What will 7593 yards come to, at 3d. per yard? 3d.759 9 value at 1s. per yard. 210)18/9 111 Or thus, 3d Ans. £9 9 11 £ s. d. 37 19 9 value at 1s. per yard. value at 3d. Ans. £9 911 value of 7593yds. at per yard 3d. per yard. 3. What is the cost of 227 yds. at 50 cents per yard? c. $ $ 50227=price at $1 per yard. $113 50c. Ans. 4. What cost 927yds. at 53 cents a yard? Note. If there be pounds also in the price: Multiply the quantity by the pounds, and to the product add the value of the quantity for the other parts of the price as in the preceding examples, and the sum will be the answer. 29. Find the value of 156yds. of cloth at £3 6s. 8d. per yard. £ 30. What is the cost of 224 yds. at £5 7s. 6d. a yard? 31. 345 yds. at 6 :: 5 :: 0 per yard=2159 :: 7 :: 6 Answers. S. d. 199:: 3 :: 4 387:: 10 :: 0 292: 8:0 GENERAL RULE II. When the price of one hundred weight, &c. is given of several denominations, to find the value of a quantity of several denominations also. Multiply the price by the integers, and take parts for the rest from the price of an integer, and the sum of the product and quotients will be the answer. EXAMPLES. 1. If 1 Cwt. cost £4 17s. 4d, what will 9 Cwt. 3qrs. 14lb. cost at the same rate? 2qrs. O is 4 17 4 price of 1 Cwt. 1qr. 0 . 9 Number of Cwt. 9. 17oz. 6pwt. 16grs. of Gold £3 16 8d. per oz. 66 8 103 10. 3 Tun 2hhd. 48 gall. of wine at £5 16 9= 11. 7 Acres 3 roods 15 rods 16 feet at £7 11s. 9d. an acre= Though the General Rules, given above, are sufficient for answering questions in Practice, yet some may perhaps be answered more easily by other rules. Several cases follow. CASE I. When the price is any even number of shillings under 24: Multiply the given quantity by half the price, and double the first figure of the product for shillings. The rest of the product will be pounds.* N. B. If the price be 2s. you need only double the unit figure for shillings. The other figures will be pounds. EXAMPLES. 1st. What will 746 yards cost at 2s. per yard? 746 Ans. £74 12 value at 2s. per yard. 10 * Suppose the price to be 16s.; as the quantity is the price at £1, the answer will be 168 of the quantity, in pounds and decimals. The decimal is to be doubled for its value in shillings, according to a previous rule. The rule is limited to 24s. because the half of a greater number, would be an inconvenient multiplier. The reason of the rules in the ten following cases is sufficiently ob Note. The above is done, by saying twice 6 (the unit figure) is 12. The other figures, viz. 74, are pounds. 2d. What will 5673yds. at 2s. per yard come to? Ans. £56 15s. 6d. N. B. Before I double the unit figure, viz. 7, I consider that a of a yard at 2s. per yard will amount to 1s. 6d. Then I double 7, which makes 14s. and 1s. 6d. added, makes 15s. 6d. The other figures are pounds. When the price wants an even part of 2s.: First find the value of the whole quantity at 2s. per pound, yard, &c. then divide it by that even part which is wanting, and subtract this quotient from the value at 2s. The remainder will be the answer. EXAMPLES. 1. What will 95 yards cost at 22d. per yard? Ans. £8 15 1 value at 1s. 10d. per yard. When there are pence in the price which are an even part of a shilling, besides an even number of shillings under 20 : First find the value of the quantity at the shillings per yard, &c. according to Case 1st. then suppose the quantity to stand as shillings per yard; divide it by that even part, which the pence are of Is. and this quotient being added to the value before found, the sum will be the answer. EXAMPLES. 1st. what will 156 yards come to, at 6s. 4d. per yard? s. d. Yds. 14d. ||156 6 £46 19 0 value of 156 yards at 6s. per yard. |