An introduction to geometry, consisting of Euclid's Elements, book i, accompanied by numerous explanations, questions, and exercises, by J. Walmsley. [With] Answers, Volumen11884 |
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Página 24
... vertex at the centre . 5. Given a finite straight line , to make an isosceles triangle with this line for one of its equal sides . ( Use Post . 3 first . ) 6. Given a finite straight line and its middle point , to draw a semicircle upon ...
... vertex at the centre . 5. Given a finite straight line , to make an isosceles triangle with this line for one of its equal sides . ( Use Post . 3 first . ) 6. Given a finite straight line and its middle point , to draw a semicircle upon ...
Página 41
... vertex ' is used in Euclid for an angle opposite to the base of a triangle . In 1-5 , Diagram IV . is referred to . ) 1. Mention four vertices of triangles which are upon the base AC . 2. Also of all the triangles upon the base CD . 3 ...
... vertex ' is used in Euclid for an angle opposite to the base of a triangle . In 1-5 , Diagram IV . is referred to . ) 1. Mention four vertices of triangles which are upon the base AC . 2. Also of all the triangles upon the base CD . 3 ...
Página 42
... vertex of each triangle be without the other triangle . A B Because , in the triangle ACD , AD is equal to AC , therefore the angle ADC is equal to the angle ACD ; ( I. 5 ) but the angle ACD is greater than the angle BCD ; ( Ax . 9 ) ...
... vertex of each triangle be without the other triangle . A B Because , in the triangle ACD , AD is equal to AC , therefore the angle ADC is equal to the angle ACD ; ( I. 5 ) but the angle ACD is greater than the angle BCD ; ( Ax . 9 ) ...
Página 43
... vertex of one triangle be upon a side of the other . This case needs no demonstration . Therefore , upon the same base , & c . Q. E. D. EXERCISE XII . 1. Does Prop.VII . deny that CA , DA in the figure can be equal ? Does it deny that ...
... vertex of one triangle be upon a side of the other . This case needs no demonstration . Therefore , upon the same base , & c . Q. E. D. EXERCISE XII . 1. Does Prop.VII . deny that CA , DA in the figure can be equal ? Does it deny that ...
Página 46
... vertices will bisect each vertical angle ( or the angle at each vertex ) . 40. PROPOSITION IX . - PROBLEM . To bisect a given rectilineal angle . Let BAC be the given rectilineal angle . It is required to bisect BAC . In AB take any ...
... vertices will bisect each vertical angle ( or the angle at each vertex ) . 40. PROPOSITION IX . - PROBLEM . To bisect a given rectilineal angle . Let BAC be the given rectilineal angle . It is required to bisect BAC . In AB take any ...
Otras ediciones - Ver todas
An Introduction to Geometry, Consisting of Euclid's Elements, Book I ... Euclides Sin vista previa disponible - 2013 |
An Introduction to Geometry, Consisting of Euclid's Elements, Book I ... Euclides Sin vista previa disponible - 2023 |
An Introduction to Geometry, Consisting of Euclid's Elements, Book I ... Euclides Sin vista previa disponible - 2018 |
Términos y frases comunes
AB is equal AC is equal adjacent angles alternate angle angle ABC angle ACB angle AGH angle BAC angle BCD angle equal angles CBA axiom base BC bisects the angle centre circle circumference Constr construction definition describe diagonal Diagram diameter enunciation equal and parallel equal angles equal sides equal to BC EQUIANGULAR POLYGONS equilateral triangle Euclid Euclid's Elements exterior four right angles Geometry given angle given point given straight line greater hypotenuse hypothesis inference isosceles triangle join less Let ABC magnitude meet middle point opposite angles opposite interior angle opposite sides pair of equal parallel to BC parallelogram perpendicular Postulate produced proof Prop proposition prove quadrilateral rectilineal figure respectively equal rhombus right angles right-angled triangle sides equal square supplementary angles theorems thesis trapezium triangle ABC triangles are equal unequal vertex Wherefore
Pasajes populares
Página 132 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Página 86 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Página 139 - If two triangles have two angles of the one equal to two angles of the other, each to each, and also one side of the one equal to the corresponding side of the other, the triangles are congruent.
Página 133 - The complements of the parallelograms, which are about the diameter of any parallelogram, are equal to one another.
Página 134 - Prove that parallelograms on the same base and between the same parallels are equal in area.
Página 134 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line ; it is required to draw a straight line through the point A, parallel to the straight hue BC.
Página 50 - if two straight lines" &c. QED COR. 1. From this it is manifest, that if two straight lines cut one another, the angles which they make at the point where they cut, are together equal to four right angles.
Página 20 - PROB. from a given point to draw a straight line equal to a given straight line. Let A be the given point, and BC the given straight line : it is required to draw from the point A a straight line equal to BC.
Página 96 - Parallelograms upon the same base and between the same parallels, are equal to one another.
Página 49 - If at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles ; then these two straight lines shall be in one and the same straight line.