Simplified Mechanics and Strength of MaterialsWiley, 1951 - 275 páginas |
Dentro del libro
Resultados 1-3 de 75
Página 73
... Table 1 . 54 - E . A wrought iron rod 1 " in diameter and 12 ′ 0 ′′ in length is subjected to a tensile load of 9,000 # . Compute its deformation . See Table 1 . 55. Factor of Safety . Suppose that we are asked to design ( determine the ...
... Table 1 . 54 - E . A wrought iron rod 1 " in diameter and 12 ′ 0 ′′ in length is subjected to a tensile load of 9,000 # . Compute its deformation . See Table 1 . 55. Factor of Safety . Suppose that we are asked to design ( determine the ...
Página 97
... tables . Thus , consider S for a 6 " x 4 " x 11⁄2 " angle section about the centroidal axis parallel to the short leg . Table 12 shows Ix - x to be 17.4in . The table also shows that the distance from the back of the short leg to the ...
... tables . Thus , consider S for a 6 " x 4 " x 11⁄2 " angle section about the centroidal axis parallel to the short leg . Table 12 shows Ix - x to be 17.4in . The table also shows that the distance from the back of the short leg to the ...
Página 208
... Table 5 and are found in many building codes . Certain blank spaces occur in this table ; where no stress is given , the bearing value exceeds the value for shear and the bearing value would have no purpose . To illustrate the use of ...
... Table 5 and are found in many building codes . Certain blank spaces occur in this table ; where no stress is given , the bearing value exceeds the value for shear and the bearing value would have no purpose . To illustrate the use of ...
Contenido
CHAPTER | 1 |
Elements of a Force | 9 |
Equilibrant | 15 |
Derechos de autor | |
Otras 64 secciones no mostradas
Otras ediciones - Ver todas
Términos y frases comunes
allowable axial load allowable load allowable unit stress angle bars center of moments centroid column compressive stresses compressive unit stress Compute the maximum concentrated load cross section cross-sectional area deflection deformation determine diameter distance double bearing elastic limit EXAMPLE EXAMPLE factor of safety fillet weld flexure formula force polygon free body diagram funicular polygon hence indicated in Fig inertia intersection length line of action linear foot magnitude material maximum bending maximum shear modulus of elasticity moment of inertia neutral surface parallel parallelogram of forces pier plate pounds per linear pounds per square pressure PROBLEMS R₁ radius of gyration reactions reinforced concrete resisting respect resultant rivet rods section modulus shaft shear diagram shearing stress shearing unit stress shown in Fig simple beam single bearing slenderness ratio SOLUTION span square inch stirrups Table tensile stresses thickness three forces truss uniformly distributed load weight width zero