Simplified Mechanics and Strength of MaterialsWiley, 1951 - 275 páginas |
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Página 2
... cross - sectional area of 8 ′′ x 8 ′′ or 64in2 ( sixty - four square inches ) as indicated in Fig . 1 ( b ) , and , if the weight of the block is distributed uniformly over the piece of wood , each square inch of cross section of wood ...
... cross - sectional area of 8 ′′ x 8 ′′ or 64in2 ( sixty - four square inches ) as indicated in Fig . 1 ( b ) , and , if the weight of the block is distributed uniformly over the piece of wood , each square inch of cross section of wood ...
Página 4
... cross - sectional area of 8 " x 8 " or 64in2 ( sixty - four square inches ) as indicated in Fig . 1 ( b ) , and , if the weight of the block is distributed uniformly over the piece of wood , each square inch of cross section of wood ...
... cross - sectional area of 8 " x 8 " or 64in2 ( sixty - four square inches ) as indicated in Fig . 1 ( b ) , and , if the weight of the block is distributed uniformly over the piece of wood , each square inch of cross section of wood ...
Página 204
... cross - sectional area of the rivet multiplied by the allowable shearing unit stress , 15,000 # / in2 , given in Table 5. The cross - sectional area of a " rivet is or 3.1416 X 0.8752 4 as πD2 4 = 0.6013in2 . Thus P = ƒ X A or P ...
... cross - sectional area of the rivet multiplied by the allowable shearing unit stress , 15,000 # / in2 , given in Table 5. The cross - sectional area of a " rivet is or 3.1416 X 0.8752 4 as πD2 4 = 0.6013in2 . Thus P = ƒ X A or P ...
Contenido
CHAPTER | 1 |
Elements of a Force | 9 |
Equilibrant | 15 |
Derechos de autor | |
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allowable axial load allowable load allowable unit stress angle bars center of moments centroid column compressive stresses compressive unit stress Compute the maximum concentrated load cross section cross-sectional area deflection deformation determine diameter distance double bearing elastic limit EXAMPLE EXAMPLE factor of safety fillet weld flexure formula force polygon free body diagram funicular polygon hence indicated in Fig inertia intersection length line of action linear foot magnitude material maximum bending maximum shear modulus of elasticity moment of inertia neutral surface parallel parallelogram of forces pier plate pounds per linear pounds per square pressure PROBLEMS R₁ radius of gyration reactions reinforced concrete resisting respect resultant rivet rods section modulus shaft shear diagram shearing stress shearing unit stress shown in Fig simple beam single bearing slenderness ratio SOLUTION span square inch stirrups Table tensile stresses thickness three forces truss uniformly distributed load weight width zero