Simplified Mechanics and Strength of MaterialsWiley, 1951 - 275 páginas |
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Página 25
... determine the magnitudes of the reactions by graphical methods . 4,000 # 1,000 # 6 ' + 8'- + 6 ' 4,000 # 9,000 # 6,000 # ( a ) 300 # 400 # 500 # 600 # 4 ' 4 ' 4 ' 4 ' ( c ) + 5 ' -5'- -5 ' ( b ) 4,000 # 2,000 # 2,000 # 10'- · 6 ' —— 6 ...
... determine the magnitudes of the reactions by graphical methods . 4,000 # 1,000 # 6 ' + 8'- + 6 ' 4,000 # 9,000 # 6,000 # ( a ) 300 # 400 # 500 # 600 # 4 ' 4 ' 4 ' 4 ' ( c ) + 5 ' -5'- -5 ' ( b ) 4,000 # 2,000 # 2,000 # 10'- · 6 ' —— 6 ...
Página 176
... determine the proper sections with respect to strength in bending only . 92 - A . A simple beam has a span of 17 ′ 0 ′′ and a uniformly distributed load of 23,000 # . Determine the size of a wide - flange steel beam to support this load ...
... determine the proper sections with respect to strength in bending only . 92 - A . A simple beam has a span of 17 ′ 0 ′′ and a uniformly distributed load of 23,000 # . Determine the size of a wide - flange steel beam to support this load ...
Página 208
... determine the allowable load , P , that this joint will safely support . SOLUTION . The following allowable working values are found in Table 15 : 34 " rivets in double shear 8 34 " rivets in double bearing on 3 " plate 3/4 " rivets in ...
... determine the allowable load , P , that this joint will safely support . SOLUTION . The following allowable working values are found in Table 15 : 34 " rivets in double shear 8 34 " rivets in double bearing on 3 " plate 3/4 " rivets in ...
Contenido
CHAPTER | 1 |
Elements of a Force | 9 |
Equilibrant | 15 |
Derechos de autor | |
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allowable axial load allowable load allowable unit stress angle bars center of moments centroid column compressive stresses compressive unit stress Compute the maximum concentrated load cross section cross-sectional area deflection deformation determine diameter distance double bearing elastic limit EXAMPLE EXAMPLE factor of safety fillet weld flexure formula force polygon free body diagram funicular polygon hence indicated in Fig inertia intersection length line of action linear foot magnitude material maximum bending maximum shear modulus of elasticity moment of inertia neutral surface parallel parallelogram of forces pier plate pounds per linear pounds per square pressure PROBLEMS R₁ radius of gyration reactions reinforced concrete resisting respect resultant rivet rods section modulus shaft shear diagram shearing stress shearing unit stress shown in Fig simple beam single bearing slenderness ratio SOLUTION span square inch stirrups Table tensile stresses thickness three forces truss uniformly distributed load weight width zero