Simplified Mechanics and Strength of MaterialsWiley, 1951 - 275 páginas |
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Página xv
... problems , design and investigation . Design problems are prob- lems in which the material , shape , and size of a body are to be determined in order that external forces may be resisted economi- cally . Problems of investigation give ...
... problems , design and investigation . Design problems are prob- lems in which the material , shape , and size of a body are to be determined in order that external forces may be resisted economi- cally . Problems of investigation give ...
Página xvi
... problem . Some problems are complex and require several steps . Never- theless , follow the above procedure for it will always serve as an aid in solving problems . There is one more important suggestion . From the beginning form the ...
... problem . Some problems are complex and require several steps . Never- theless , follow the above procedure for it will always serve as an aid in solving problems . There is one more important suggestion . From the beginning form the ...
Página 50
... problems , where both the loads and reactions are vertical , the sum of the loads equals the sum of the reactions . Most of the previous problems in this text have been solved graphically , by the construction of diagrams . The accuracy ...
... problems , where both the loads and reactions are vertical , the sum of the loads equals the sum of the reactions . Most of the previous problems in this text have been solved graphically , by the construction of diagrams . The accuracy ...
Contenido
CHAPTER | 1 |
Elements of a Force | 9 |
Equilibrant | 15 |
Derechos de autor | |
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allowable axial load allowable load allowable unit stress angle bars center of moments centroid column compressive stresses compressive unit stress Compute the maximum concentrated load cross section cross-sectional area deflection deformation determine diameter distance double bearing elastic limit EXAMPLE EXAMPLE factor of safety fillet weld flexure formula force polygon free body diagram funicular polygon hence indicated in Fig inertia intersection length line of action linear foot magnitude material maximum bending maximum shear modulus of elasticity moment of inertia neutral surface parallel parallelogram of forces pier plate pounds per linear pounds per square pressure PROBLEMS R₁ radius of gyration reactions reinforced concrete resisting respect resultant rivet rods section modulus shaft shear diagram shearing stress shearing unit stress shown in Fig simple beam single bearing slenderness ratio SOLUTION span square inch stirrups Table tensile stresses thickness three forces truss uniformly distributed load weight width zero